YumYum247
  • YumYum247
1
Physics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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YumYum247
  • YumYum247
Let me try my luck first.....
YumYum247
  • YumYum247
319Hz?
YumYum247
  • YumYum247
idk:(

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More answers

Astrophysics
  • Astrophysics
Your beat frequency is just changed
Astrophysics
  • Astrophysics
but the steps are initially the same
YumYum247
  • YumYum247
from 2 to 1Hz???????
Astrophysics
  • Astrophysics
Yup
YumYum247
  • YumYum247
give me a hint please.
Astrophysics
  • Astrophysics
\[1 Hz = |f_2-f_1|\]
YumYum247
  • YumYum247
that's what i was using OMG!!!
YumYum247
  • YumYum247
Awwwwnnnn!!! :"(
Astrophysics
  • Astrophysics
lol
Astrophysics
  • Astrophysics
What did we get for frequency b
Astrophysics
  • Astrophysics
322 and 318?
YumYum247
  • YumYum247
both are viable
YumYum247
  • YumYum247
but i guess 322Hz seems legit to me.
Astrophysics
  • Astrophysics
I got it, I'll let you think about it for a bit
YumYum247
  • YumYum247
ok but the formula is right tho?????right??
Astrophysics
  • Astrophysics
We don't need a formula, all we have to observe is the frequencies dropping 1 Hz
Astrophysics
  • Astrophysics
from the original
Astrophysics
  • Astrophysics
We figured out the frequencies were 322 and 318
YumYum247
  • YumYum247
ok so in the initial case the freak was 322Hz and beat freak was 2Hz but then it droped to 1Hz
Astrophysics
  • Astrophysics
So we have 318 drops to 317 and 322 drops to 321, now if we have beat frequency being 1 Hz, we have the following \[320Hz-317Hz = 1 Hz\] or is it \[321 Hz - 320 Hz = 1 Hz\] which one can we eliminate
YumYum247
  • YumYum247
second one would be it.
Astrophysics
  • Astrophysics
Yes, you're right, so our original frequency then is 322 Hz, notice the question specifies, tuning fork B AND beat frequency dropped 1 Hz. We just had to read it carefully :)
YumYum247
  • YumYum247
ooooooooooh i got it.....
YumYum247
  • YumYum247
so in the first case we got 322 and 318 and the beat freak was 2Hz but then then the beat freak droped to 1 Hz
Astrophysics
  • Astrophysics
Yes, as well did the frequency of b
Astrophysics
  • Astrophysics
they both dropped by 1, it's a nice question
Astrophysics
  • Astrophysics
It checks if you understand the concept or not :P
YumYum247
  • YumYum247
initially we had 320Hz + 2 beat freak = 322 bt then it drooped by 1Hz
Astrophysics
  • Astrophysics
Yes, that's what we figured out from the previous question, we had two frequencies for b and we had to decipher which one was the original
YumYum247
  • YumYum247
so 321 - inital 320 = 1Hz
Astrophysics
  • Astrophysics
Frequency A was 320Hz, not B
Astrophysics
  • Astrophysics
We figured out frequency b in your previous problem to be 322, and 318
YumYum247
  • YumYum247
yah that's what i meant!!!
Astrophysics
  • Astrophysics
and it told us in this part that frequency b and the beat frequency both drop by 1 hz
Astrophysics
  • Astrophysics
ok do you get it now? :)
YumYum247
  • YumYum247
79.329% but yah i think i got it.
Astrophysics
  • Astrophysics
Ok :)
YumYum247
  • YumYum247
Thanks an...just one more :")
Astrophysics
  • Astrophysics
>.<
Astrophysics
  • Astrophysics
Ok haha
YumYum247
  • YumYum247
I'm sorry love but we have to go through this together.....!! :") LOL
YumYum247
  • YumYum247
i've done the whole question but i'm just stuck at the line part. can you teach me how to do the calculations at the very end...here is a demo.
Astrophysics
  • Astrophysics
Other post!
Astrophysics
  • Astrophysics
:)
YumYum247
  • YumYum247
|dw:1436341077195:dw|
Astrophysics
  • Astrophysics
You need to find the difference
Astrophysics
  • Astrophysics
That's just of the drill
YumYum247
  • YumYum247
no i mean how do i punch the numbers into my calclators????
Astrophysics
  • Astrophysics
Oooh I see
Astrophysics
  • Astrophysics
It requires logarithm rules to make it clear we should put brackets \[90 = 10 \log \left( \frac{ I_r }{ I_d } \right)\] we are taking log of base 10, first thing lets get rid of the 10 by dividing by 10 on both sides \[9 = \log \left( \frac{ I_r }{ I_d } \right)\] now we can convert it to exponential form \[10^9 = \frac{ I_r }{ I_d }\]
YumYum247
  • YumYum247
ok i understood that you divided both sides by 10...but how did you get from 9 to 10^9?
YumYum247
  • YumYum247
can you say like "press log and then something....i'll follow you how you did it.
Astrophysics
  • Astrophysics
I used the following property \[\huge f(f^{-1}(x)) = 10^{\log_{10}x} = x\]
Astrophysics
  • Astrophysics
We're just taking the inverse
YumYum247
  • YumYum247
inverse of 9
Astrophysics
  • Astrophysics
No of the logarithm function
Astrophysics
  • Astrophysics
If you have your calculator on you, notice that there's a "Log" button
YumYum247
  • YumYum247
ok
Astrophysics
  • Astrophysics
if you put 2nd log that will give you the exponential function
YumYum247
  • YumYum247
yes i;m holding it
Astrophysics
  • Astrophysics
That's what we're basically doing, cancelling out the logarithm
YumYum247
  • YumYum247
yes there is
Astrophysics
  • Astrophysics
by taking it's inverse which is the exponential function
YumYum247
  • YumYum247
so 2nd log?
Astrophysics
  • Astrophysics
Yes, but to make intuitive, think of it like this |dw:1436331095538:dw| sort of like this
Astrophysics
  • Astrophysics
We're doing the same thing with logarithm there
YumYum247
  • YumYum247
ok
Astrophysics
  • Astrophysics
10^9, that's a huge number a billion actually..
YumYum247
  • YumYum247
so 9 2nd log?
Astrophysics
  • Astrophysics
No 2nd log then 9
Astrophysics
  • Astrophysics
\[\frac{ I_r }{ I_d } = 10^9\]
YumYum247
  • YumYum247
no my calculator is different....i'm getting some 1000000000000 as a answer
YumYum247
  • YumYum247
so the rocket launcher is 9 or 100000000000times intense????
YumYum247
  • YumYum247
compared to drilling???????????
Astrophysics
  • Astrophysics
a billion times more intense yeah lol
Astrophysics
  • Astrophysics
1,000,000,000
YumYum247
  • YumYum247
mother of garden!!! that's insane!!!
YumYum247
  • YumYum247
so each nod on the db scale goes up by 10.
YumYum247
  • YumYum247
for exapmple the differernce between 1db and 2 is 20 times the intensity difference???
Astrophysics
  • Astrophysics
|dw:1436331490707:dw| just a comparison of the scale
YumYum247
  • YumYum247
You trully saved my life.........Thank yo infinite.....
YumYum247
  • YumYum247
Thank you 8-> much
YumYum247
  • YumYum247
oo-> mch
YumYum247
  • YumYum247
how did you become so smart???????????????
Astrophysics
  • Astrophysics
Lol I am not smart, I consider myself pretty dumb! :)
YumYum247
  • YumYum247
shush........you should be working in some google company
Astrophysics
  • Astrophysics
Haha, I wish xD, thank you for the compliment and you're welcome! And a way I gooooo....|dw:1436331812585:dw|
YumYum247
  • YumYum247
hey write something about yourself, so people know who you are and where your from????
YumYum247
  • YumYum247
Man i gotta say this but whoever created this universe is a effin genius!!!
Astrophysics
  • Astrophysics
Well, I don't really think all that is important, I just like to help people :)
Astrophysics
  • Astrophysics
...also I'm a bit lazy!
YumYum247
  • YumYum247
LOL well you have something in common!!! :"D
Astrophysics
  • Astrophysics
hehe
YumYum247
  • YumYum247
no i mean i looked at your gif and it just gave me chills to think who could possibly create something massive as a universe.
Astrophysics
  • Astrophysics
How do you know someone created it :p :D :O
YumYum247
  • YumYum247
well nothing really pops up out of nowhere.....
Astrophysics
  • Astrophysics
Ok :)
YumYum247
  • YumYum247
the discipline and the order/manner of everything is what really gets me.
YumYum247
  • YumYum247
and that's what Einstein was really fascinated about.....he said nothing really had to be this way.......
YumYum247
  • YumYum247
anyways i think i'm starting to eat your brain now....LOL Thank you shooooooo mch!!!! please stay cute as always and i hope i see you again....:")
YumYum247
  • YumYum247
soo, Goodnoght!!!!
Astrophysics
  • Astrophysics
Hey, no it's good, at least you're thinking about this stuff now! Take care :)

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