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YumYum247
 one year ago
1
YumYum247
 one year ago
1

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Let me try my luck first.....

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Your beat frequency is just changed

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1but the steps are initially the same

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1from 2 to 1Hz???????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1give me a hint please.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[1 Hz = f_2f_1\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1that's what i was using OMG!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1What did we get for frequency b

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1but i guess 322Hz seems legit to me.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I got it, I'll let you think about it for a bit

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok but the formula is right tho?????right??

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We don't need a formula, all we have to observe is the frequencies dropping 1 Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1from the original

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We figured out the frequencies were 322 and 318

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok so in the initial case the freak was 322Hz and beat freak was 2Hz but then it droped to 1Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So we have 318 drops to 317 and 322 drops to 321, now if we have beat frequency being 1 Hz, we have the following \[320Hz317Hz = 1 Hz\] or is it \[321 Hz  320 Hz = 1 Hz\] which one can we eliminate

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1second one would be it.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, you're right, so our original frequency then is 322 Hz, notice the question specifies, tuning fork B AND beat frequency dropped 1 Hz. We just had to read it carefully :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ooooooooooh i got it.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so in the first case we got 322 and 318 and the beat freak was 2Hz but then then the beat freak droped to 1 Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, as well did the frequency of b

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1they both dropped by 1, it's a nice question

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1It checks if you understand the concept or not :P

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1initially we had 320Hz + 2 beat freak = 322 bt then it drooped by 1Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, that's what we figured out from the previous question, we had two frequencies for b and we had to decipher which one was the original

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so 321  inital 320 = 1Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Frequency A was 320Hz, not B

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We figured out frequency b in your previous problem to be 322, and 318

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yah that's what i meant!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1and it told us in this part that frequency b and the beat frequency both drop by 1 hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1ok do you get it now? :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.179.329% but yah i think i got it.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Thanks an...just one more :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1I'm sorry love but we have to go through this together.....!! :") LOL

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i've done the whole question but i'm just stuck at the line part. can you teach me how to do the calculations at the very end...here is a demo.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436341077195:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You need to find the difference

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's just of the drill

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1no i mean how do i punch the numbers into my calclators????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1It requires logarithm rules to make it clear we should put brackets \[90 = 10 \log \left( \frac{ I_r }{ I_d } \right)\] we are taking log of base 10, first thing lets get rid of the 10 by dividing by 10 on both sides \[9 = \log \left( \frac{ I_r }{ I_d } \right)\] now we can convert it to exponential form \[10^9 = \frac{ I_r }{ I_d }\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok i understood that you divided both sides by 10...but how did you get from 9 to 10^9?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1can you say like "press log and then something....i'll follow you how you did it.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I used the following property \[\huge f(f^{1}(x)) = 10^{\log_{10}x} = x\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We're just taking the inverse

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No of the logarithm function

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1If you have your calculator on you, notice that there's a "Log" button

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1if you put 2nd log that will give you the exponential function

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's what we're basically doing, cancelling out the logarithm

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1by taking it's inverse which is the exponential function

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, but to make intuitive, think of it like this dw:1436331095538:dw sort of like this

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We're doing the same thing with logarithm there

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.110^9, that's a huge number a billion actually..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No 2nd log then 9

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ I_r }{ I_d } = 10^9\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1no my calculator is different....i'm getting some 1000000000000 as a answer

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so the rocket launcher is 9 or 100000000000times intense????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1compared to drilling???????????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1a billion times more intense yeah lol

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1mother of garden!!! that's insane!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so each nod on the db scale goes up by 10.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1for exapmple the differernce between 1db and 2 is 20 times the intensity difference???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436331490707:dw just a comparison of the scale

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1You trully saved my life.........Thank yo infinite.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1how did you become so smart???????????????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Lol I am not smart, I consider myself pretty dumb! :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1shush........you should be working in some google company

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Haha, I wish xD, thank you for the compliment and you're welcome! And a way I gooooo....dw:1436331812585:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1hey write something about yourself, so people know who you are and where your from????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Man i gotta say this but whoever created this universe is a effin genius!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Well, I don't really think all that is important, I just like to help people :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1...also I'm a bit lazy!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1LOL well you have something in common!!! :"D

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1no i mean i looked at your gif and it just gave me chills to think who could possibly create something massive as a universe.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1How do you know someone created it :p :D :O

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1well nothing really pops up out of nowhere.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1the discipline and the order/manner of everything is what really gets me.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1and that's what Einstein was really fascinated about.....he said nothing really had to be this way.......

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1anyways i think i'm starting to eat your brain now....LOL Thank you shooooooo mch!!!! please stay cute as always and i hope i see you again....:")

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, no it's good, at least you're thinking about this stuff now! Take care :)
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