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YumYum247

  • one year ago

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  1. YumYum247
    • one year ago
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    Let me try my luck first.....

  2. YumYum247
    • one year ago
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    319Hz?

  3. YumYum247
    • one year ago
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    idk:(

  4. Astrophysics
    • one year ago
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    Your beat frequency is just changed

  5. Astrophysics
    • one year ago
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    but the steps are initially the same

  6. YumYum247
    • one year ago
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    from 2 to 1Hz???????

  7. Astrophysics
    • one year ago
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    Yup

  8. YumYum247
    • one year ago
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    give me a hint please.

  9. Astrophysics
    • one year ago
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    \[1 Hz = |f_2-f_1|\]

  10. YumYum247
    • one year ago
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    that's what i was using OMG!!!

  11. YumYum247
    • one year ago
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    Awwwwnnnn!!! :"(

  12. Astrophysics
    • one year ago
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    lol

  13. Astrophysics
    • one year ago
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    What did we get for frequency b

  14. Astrophysics
    • one year ago
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    322 and 318?

  15. YumYum247
    • one year ago
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    both are viable

  16. YumYum247
    • one year ago
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    but i guess 322Hz seems legit to me.

  17. Astrophysics
    • one year ago
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    I got it, I'll let you think about it for a bit

  18. YumYum247
    • one year ago
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    ok but the formula is right tho?????right??

  19. Astrophysics
    • one year ago
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    We don't need a formula, all we have to observe is the frequencies dropping 1 Hz

  20. Astrophysics
    • one year ago
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    from the original

  21. Astrophysics
    • one year ago
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    We figured out the frequencies were 322 and 318

  22. YumYum247
    • one year ago
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    ok so in the initial case the freak was 322Hz and beat freak was 2Hz but then it droped to 1Hz

  23. Astrophysics
    • one year ago
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    So we have 318 drops to 317 and 322 drops to 321, now if we have beat frequency being 1 Hz, we have the following \[320Hz-317Hz = 1 Hz\] or is it \[321 Hz - 320 Hz = 1 Hz\] which one can we eliminate

  24. YumYum247
    • one year ago
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    second one would be it.

  25. Astrophysics
    • one year ago
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    Yes, you're right, so our original frequency then is 322 Hz, notice the question specifies, tuning fork B AND beat frequency dropped 1 Hz. We just had to read it carefully :)

  26. YumYum247
    • one year ago
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    ooooooooooh i got it.....

  27. YumYum247
    • one year ago
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    so in the first case we got 322 and 318 and the beat freak was 2Hz but then then the beat freak droped to 1 Hz

  28. Astrophysics
    • one year ago
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    Yes, as well did the frequency of b

  29. Astrophysics
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    they both dropped by 1, it's a nice question

  30. Astrophysics
    • one year ago
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    It checks if you understand the concept or not :P

  31. YumYum247
    • one year ago
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    initially we had 320Hz + 2 beat freak = 322 bt then it drooped by 1Hz

  32. Astrophysics
    • one year ago
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    Yes, that's what we figured out from the previous question, we had two frequencies for b and we had to decipher which one was the original

  33. YumYum247
    • one year ago
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    so 321 - inital 320 = 1Hz

  34. Astrophysics
    • one year ago
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    Frequency A was 320Hz, not B

  35. Astrophysics
    • one year ago
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    We figured out frequency b in your previous problem to be 322, and 318

  36. YumYum247
    • one year ago
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    yah that's what i meant!!!

  37. Astrophysics
    • one year ago
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    and it told us in this part that frequency b and the beat frequency both drop by 1 hz

  38. Astrophysics
    • one year ago
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    ok do you get it now? :)

  39. YumYum247
    • one year ago
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    79.329% but yah i think i got it.

  40. Astrophysics
    • one year ago
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    Ok :)

  41. YumYum247
    • one year ago
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    Thanks an...just one more :")

  42. Astrophysics
    • one year ago
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    >.<

  43. Astrophysics
    • one year ago
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    Ok haha

  44. YumYum247
    • one year ago
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    I'm sorry love but we have to go through this together.....!! :") LOL

  45. YumYum247
    • one year ago
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    i've done the whole question but i'm just stuck at the line part. can you teach me how to do the calculations at the very end...here is a demo.

  46. Astrophysics
    • one year ago
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    Other post!

  47. Astrophysics
    • one year ago
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    :)

  48. YumYum247
    • one year ago
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    |dw:1436341077195:dw|

  49. Astrophysics
    • one year ago
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    You need to find the difference

  50. Astrophysics
    • one year ago
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    That's just of the drill

  51. YumYum247
    • one year ago
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    no i mean how do i punch the numbers into my calclators????

  52. Astrophysics
    • one year ago
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    Oooh I see

  53. Astrophysics
    • one year ago
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    It requires logarithm rules to make it clear we should put brackets \[90 = 10 \log \left( \frac{ I_r }{ I_d } \right)\] we are taking log of base 10, first thing lets get rid of the 10 by dividing by 10 on both sides \[9 = \log \left( \frac{ I_r }{ I_d } \right)\] now we can convert it to exponential form \[10^9 = \frac{ I_r }{ I_d }\]

  54. YumYum247
    • one year ago
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    ok i understood that you divided both sides by 10...but how did you get from 9 to 10^9?

  55. YumYum247
    • one year ago
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    can you say like "press log and then something....i'll follow you how you did it.

  56. Astrophysics
    • one year ago
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    I used the following property \[\huge f(f^{-1}(x)) = 10^{\log_{10}x} = x\]

  57. Astrophysics
    • one year ago
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    We're just taking the inverse

  58. YumYum247
    • one year ago
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    inverse of 9

  59. Astrophysics
    • one year ago
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    No of the logarithm function

  60. Astrophysics
    • one year ago
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    If you have your calculator on you, notice that there's a "Log" button

  61. YumYum247
    • one year ago
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    ok

  62. Astrophysics
    • one year ago
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    if you put 2nd log that will give you the exponential function

  63. YumYum247
    • one year ago
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    yes i;m holding it

  64. Astrophysics
    • one year ago
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    That's what we're basically doing, cancelling out the logarithm

  65. YumYum247
    • one year ago
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    yes there is

  66. Astrophysics
    • one year ago
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    by taking it's inverse which is the exponential function

  67. YumYum247
    • one year ago
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    so 2nd log?

  68. Astrophysics
    • one year ago
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    Yes, but to make intuitive, think of it like this |dw:1436331095538:dw| sort of like this

  69. Astrophysics
    • one year ago
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    We're doing the same thing with logarithm there

  70. YumYum247
    • one year ago
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    ok

  71. Astrophysics
    • one year ago
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    10^9, that's a huge number a billion actually..

  72. YumYum247
    • one year ago
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    so 9 2nd log?

  73. Astrophysics
    • one year ago
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    No 2nd log then 9

  74. Astrophysics
    • one year ago
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    \[\frac{ I_r }{ I_d } = 10^9\]

  75. YumYum247
    • one year ago
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    no my calculator is different....i'm getting some 1000000000000 as a answer

  76. YumYum247
    • one year ago
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    so the rocket launcher is 9 or 100000000000times intense????

  77. YumYum247
    • one year ago
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    compared to drilling???????????

  78. Astrophysics
    • one year ago
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    a billion times more intense yeah lol

  79. Astrophysics
    • one year ago
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    1,000,000,000

  80. YumYum247
    • one year ago
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    mother of garden!!! that's insane!!!

  81. YumYum247
    • one year ago
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    so each nod on the db scale goes up by 10.

  82. YumYum247
    • one year ago
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    for exapmple the differernce between 1db and 2 is 20 times the intensity difference???

  83. Astrophysics
    • one year ago
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    |dw:1436331490707:dw| just a comparison of the scale

  84. YumYum247
    • one year ago
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    You trully saved my life.........Thank yo infinite.....

  85. YumYum247
    • one year ago
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    Thank you 8-> much

  86. YumYum247
    • one year ago
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    oo-> mch

  87. YumYum247
    • one year ago
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    how did you become so smart???????????????

  88. Astrophysics
    • one year ago
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    Lol I am not smart, I consider myself pretty dumb! :)

  89. YumYum247
    • one year ago
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    shush........you should be working in some google company

  90. Astrophysics
    • one year ago
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    Haha, I wish xD, thank you for the compliment and you're welcome! And a way I gooooo....|dw:1436331812585:dw|

  91. YumYum247
    • one year ago
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    hey write something about yourself, so people know who you are and where your from????

  92. YumYum247
    • one year ago
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    Man i gotta say this but whoever created this universe is a effin genius!!!

  93. Astrophysics
    • one year ago
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    Well, I don't really think all that is important, I just like to help people :)

  94. Astrophysics
    • one year ago
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    ...also I'm a bit lazy!

  95. YumYum247
    • one year ago
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    LOL well you have something in common!!! :"D

  96. Astrophysics
    • one year ago
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    hehe

  97. YumYum247
    • one year ago
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    no i mean i looked at your gif and it just gave me chills to think who could possibly create something massive as a universe.

  98. Astrophysics
    • one year ago
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    How do you know someone created it :p :D :O

  99. YumYum247
    • one year ago
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    well nothing really pops up out of nowhere.....

  100. Astrophysics
    • one year ago
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    Ok :)

  101. YumYum247
    • one year ago
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    the discipline and the order/manner of everything is what really gets me.

  102. YumYum247
    • one year ago
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    and that's what Einstein was really fascinated about.....he said nothing really had to be this way.......

  103. YumYum247
    • one year ago
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    anyways i think i'm starting to eat your brain now....LOL Thank you shooooooo mch!!!! please stay cute as always and i hope i see you again....:")

  104. YumYum247
    • one year ago
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    soo, Goodnoght!!!!

  105. Astrophysics
    • one year ago
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    Hey, no it's good, at least you're thinking about this stuff now! Take care :)

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