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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    Options are: -3,000 -2,000 2,000 3,000

  3. anonymous
    • one year ago
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    the answer would be the slope.

  4. anonymous
    • one year ago
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    Do you know the slope formula?

  5. anonymous
    • one year ago
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    y-y1=m(x-x1)

  6. anonymous
    • one year ago
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    \[\frac{ y _{1}^2 - y_{2}^2 }{ x_{1}^2 - x_{2}^2 }\]

  7. anonymous
    • one year ago
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    ohh that one

  8. anonymous
    • one year ago
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    What you put was the point slope formula

  9. anonymous
    • one year ago
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    not formula, but more of a form. Anyway, you would pick 2 points on the graph.

  10. anonymous
    • one year ago
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    So now this is where I dont know how which is y and x

  11. anonymous
    • one year ago
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    Okay ill walk you through. Pick two points.

  12. anonymous
    • one year ago
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    oh okay so (0,80,000) and (10,50,000)

  13. anonymous
    • one year ago
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    Okay. So our Y's are 80,000 and 50,000. Notice that there is a y1 and x1 and y2 and x2. These correspond, so you cannot randomly put them in whatever order you want. So we will do this 80,000-50,000. Our corresponding x's are 0 and 10, so they go under, as so. \[\frac{ 80,000 - 50,000 }{ 0- 10}\]

  14. anonymous
    • one year ago
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    I just did it and I got 3.. for 3,000

  15. anonymous
    • one year ago
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    -3,000 actually because its goin down

  16. anonymous
    • one year ago
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    Correct?

  17. anonymous
    • one year ago
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    well, you have forgotten one thing. when you subtract 0-10, equals NEGATIVE 10. so it is -3000 like you stated.

  18. anonymous
    • one year ago
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    Thank you!

  19. anonymous
    • one year ago
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    Np

  20. anonymous
    • one year ago
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    You know thats all I have trouble with, finding what formula to use

  21. anonymous
    • one year ago
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    do more practice problems, it will help a lot. the more often you start using the right ones in the right situations, you will get better at it.

  22. anonymous
    • one year ago
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    okay

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spraguer (Moderator)
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