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Saylilbaby

  • one year ago

intervals of increasing and decreasing, intervals of positive and negative, and extrema of F(x)=3/x^2-4+1

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  1. saylilbaby
    • one year ago
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    @ganeshie8 @CGGURUMANJUNATH @Astrophysics

  2. saylilbaby
    • one year ago
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    @Owlcoffee

  3. saylilbaby
    • one year ago
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    just need this part @Owlcoffee intervals of positive and negative, and extrema of F(x)=3/x^2-4+1

  4. saylilbaby
    • one year ago
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    @Data_LG2

  5. Owlcoffee
    • one year ago
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    Well, you find the increase or decrease of any function, by derivating it. So, begin by derivating the function.

  6. saylilbaby
    • one year ago
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    i did the increasing and decreasing i just need the positive and negitive and extrema @Owlcoffee

  7. Owlcoffee
    • one year ago
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    You still require to derivate the function and analyze the sign of it.

  8. saylilbaby
    • one year ago
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    how i do that @Owlcoffee

  9. Owlcoffee
    • one year ago
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    Find the derivative first, what did you get?

  10. saylilbaby
    • one year ago
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    -6x/(x^2-4)^2 @Owlcoffee

  11. Owlcoffee
    • one year ago
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    Okay, so now, you have to analyze the sign of each part, first the numerator and then the denominator. \[-6x=0\] \[x^2-4 \neq 0\]

  12. saylilbaby
    • one year ago
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    how i do that @Owlcoffee

  13. Owlcoffee
    • one year ago
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    I'll give you the example usingthe numerator: \[-6x=0\] This is the numerator, and I can allow myself for it to be zero because it does not have problem with the existance, so I will only solve for "x": \[x=\frac{ 0 }{ -6 }\] \[x=0 \] Now, with the value of "x" that makes the numerator 0 I will draw a line that represent all the values of the "x" axis and what sign they image have: |dw:1436333122105:dw| So, this is what is called "studying the sign", which implies that I don't care what value the images of x gives, I am only interested in the sign, and by looking at the numerator, I know that when x tends towards inifnity the values will be negative and when it tends towards negative infinitiy they become positive.

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