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anonymous
 one year ago
intervals of increasing and decreasing,
intervals of positive and negative, and extrema of F(x)=3/x^24+1
anonymous
 one year ago
intervals of increasing and decreasing, intervals of positive and negative, and extrema of F(x)=3/x^24+1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @CGGURUMANJUNATH @Astrophysics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just need this part @Owlcoffee intervals of positive and negative, and extrema of F(x)=3/x^24+1

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Well, you find the increase or decrease of any function, by derivating it. So, begin by derivating the function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did the increasing and decreasing i just need the positive and negitive and extrema @Owlcoffee

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1You still require to derivate the function and analyze the sign of it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how i do that @Owlcoffee

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Find the derivative first, what did you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06x/(x^24)^2 @Owlcoffee

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Okay, so now, you have to analyze the sign of each part, first the numerator and then the denominator. \[6x=0\] \[x^24 \neq 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how i do that @Owlcoffee

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1I'll give you the example usingthe numerator: \[6x=0\] This is the numerator, and I can allow myself for it to be zero because it does not have problem with the existance, so I will only solve for "x": \[x=\frac{ 0 }{ 6 }\] \[x=0 \] Now, with the value of "x" that makes the numerator 0 I will draw a line that represent all the values of the "x" axis and what sign they image have: dw:1436333122105:dw So, this is what is called "studying the sign", which implies that I don't care what value the images of x gives, I am only interested in the sign, and by looking at the numerator, I know that when x tends towards inifnity the values will be negative and when it tends towards negative infinitiy they become positive.
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