anonymous
  • anonymous
combi principles
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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dan815
  • dan815
: )
ganeshie8
  • ganeshie8
how many letters are there ? how many digits are there ? the question is ambiguous yeah
dan815
  • dan815
http://prntscr.com/7q5o2w there is one

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anonymous
  • anonymous
You're right @ganeshie8 =)
anonymous
  • anonymous
@dan815 why is it 10? =)
dan815
  • dan815
10 digits http://prntscr.com/7q5ox0 there is 2
dan815
  • dan815
are you trying to trick us with this question?
dan815
  • dan815
you can try the rest on your own, its the same method
anonymous
  • anonymous
No no it is really the question
ganeshie8
  • ganeshie8
what is the question
ganeshie8
  • ganeshie8
hey is that a new question ?
ganeshie8
  • ganeshie8
3 jackets 6 shirts 4 pants total how many possibilities are there for buying "one" item ?
anonymous
  • anonymous
It seems like the first question is a unintelligible. So i posted the last one.
ganeshie8
  • ganeshie8
Yep! one item to choose from 13 items so one of the items can be chosen in 13C1 = 13 ways
ganeshie8
  • ganeshie8
for part b, you need to multiply them : 3C1*6C1*4C1 = 3*6*4 = 72
anonymous
  • anonymous
yezzz how about the 4th question
anonymous
  • anonymous
12c1?
anonymous
  • anonymous
oh its like the fifth question though
ganeshie8
  • ganeshie8
12C1 = 12 for parta looks good
ganeshie8
  • ganeshie8
16 ppl total one class representative can be chosen in 16C1 = 16 ways
ganeshie8
  • ganeshie8
for partb : one male class representative and one female class representative can be chosen in : 8C1*6C1 = 8*6 = 48 ways
anonymous
  • anonymous
?
ganeshie8
  • ganeshie8
nope, your answer for b is wrong
anonymous
  • anonymous
is it 14c2?
ganeshie8
  • ganeshie8
First of all, whats your interpretation of the problem ?
ganeshie8
  • ganeshie8
we need to choose two class representative, one from each gender, yes ?
anonymous
  • anonymous
yes yes
ganeshie8
  • ganeshie8
whats your answer for part b ?
anonymous
  • anonymous
its 48 ways
ganeshie8
  • ganeshie8
good
ganeshie8
  • ganeshie8
for partc, we just need to choose 2 students, gender doesn't matter
ganeshie8
  • ganeshie8
Yes, 2 students can be chosen from 14 students in 14C2 ways.
anonymous
  • anonymous
the road
ganeshie8
  • ganeshie8
|dw:1436339681059:dw|
ganeshie8
  • ganeshie8
Suppose A is your home, C is your school and B is an icecream shop on the way
ganeshie8
  • ganeshie8
parta is asking you to find out the number of paths between A and C
anonymous
  • anonymous
Okay.. Im following. =)
ganeshie8
  • ganeshie8
Make a guess, how many total paths are there ?
ganeshie8
  • ganeshie8
Nope. Notice that for every path from A to B, there are 4 paths from B to C : |dw:1436340238276:dw|
ganeshie8
  • ganeshie8
since there are 6 paths from A to B, the total number of paths from A to C will be simply 6*4 = 24
ganeshie8
  • ganeshie8
read the question again what do we need to find for parta ?
ganeshie8
  • ganeshie8
it is just asking you to find the number of paths from A to C through B
ganeshie8
  • ganeshie8
there are 24 paths so the answer is 24
ganeshie8
  • ganeshie8
Easy ok
ganeshie8
  • ganeshie8
can you try partb ?
anonymous
  • anonymous
part? you mean..
ganeshie8
  • ganeshie8
|dw:1436343105994:dw|
ganeshie8
  • ganeshie8
A to C, there are 6*4 = 24 paths C to A, again there are 4*6 = 24 paths so for a round trip, there are 24*24 distinct paths
anonymous
  • anonymous
Thank you so much @ganeshie8 =)

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