combi principles

- anonymous

combi principles

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- schrodinger

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- dan815

: )

- ganeshie8

how many letters are there ?
how many digits are there ?
the question is ambiguous yeah

- dan815

http://prntscr.com/7q5o2w there is one

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## More answers

- anonymous

You're right @ganeshie8 =)

- anonymous

@dan815 why is it 10? =)

- dan815

10 digits
http://prntscr.com/7q5ox0 there is 2

- dan815

are you trying to trick us with this question?

- dan815

you can try the rest on your own, its the same method

- anonymous

No no it is really the question

- ganeshie8

what is the question

- ganeshie8

hey is that a new question ?

- ganeshie8

3 jackets
6 shirts
4 pants
total how many possibilities are there for buying "one" item ?

- anonymous

It seems like the first question is a unintelligible. So i posted the last one.

- ganeshie8

Yep! one item to choose from 13 items
so one of the items can be chosen in 13C1 = 13 ways

- ganeshie8

for part b, you need to multiply them :
3C1*6C1*4C1 = 3*6*4 = 72

- anonymous

yezzz how about the 4th question

- anonymous

12c1?

- anonymous

oh its like the fifth question though

- ganeshie8

12C1 = 12
for parta looks good

- ganeshie8

16 ppl total
one class representative can be chosen in 16C1 = 16 ways

- ganeshie8

for partb :
one male class representative and one female class representative can be chosen in : 8C1*6C1 = 8*6 = 48 ways

- anonymous

?

- ganeshie8

nope, your answer for b is wrong

- anonymous

is it 14c2?

- ganeshie8

First of all, whats your interpretation of the problem ?

- ganeshie8

we need to choose two class representative, one from each gender, yes ?

- anonymous

yes yes

- ganeshie8

whats your answer for part b ?

- anonymous

its 48 ways

- ganeshie8

good

- ganeshie8

for partc, we just need to choose 2 students, gender doesn't matter

- ganeshie8

Yes, 2 students can be chosen from 14 students in 14C2 ways.

- anonymous

the road

- ganeshie8

|dw:1436339681059:dw|

- ganeshie8

Suppose A is your home,
C is your school
and B is an icecream shop on the way

- ganeshie8

parta is asking you to find out the number of paths between A and C

- anonymous

Okay.. Im following. =)

- ganeshie8

Make a guess, how many total paths are there ?

- ganeshie8

Nope. Notice that for every path from A to B,
there are 4 paths from B to C :
|dw:1436340238276:dw|

- ganeshie8

since there are 6 paths from A to B,
the total number of paths from A to C will be simply 6*4 = 24

- ganeshie8

read the question again
what do we need to find for parta ?

- ganeshie8

it is just asking you to find the number of paths from A to C through B

- ganeshie8

there are 24 paths
so the answer is 24

- ganeshie8

Easy ok

- ganeshie8

can you try partb ?

- anonymous

part? you mean..

- ganeshie8

|dw:1436343105994:dw|

- ganeshie8

A to C, there are 6*4 = 24 paths
C to A, again there are 4*6 = 24 paths
so for a round trip, there are 24*24 distinct paths

- anonymous

Thank you so much @ganeshie8 =)

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