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anonymous

  • one year ago

combi principles

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  1. dan815
    • one year ago
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    : )

  2. ganeshie8
    • one year ago
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    how many letters are there ? how many digits are there ? the question is ambiguous yeah

  3. dan815
    • one year ago
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    http://prntscr.com/7q5o2w there is one

  4. anonymous
    • one year ago
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    You're right @ganeshie8 =)

  5. anonymous
    • one year ago
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    @dan815 why is it 10? =)

  6. dan815
    • one year ago
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    10 digits http://prntscr.com/7q5ox0 there is 2

  7. dan815
    • one year ago
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    are you trying to trick us with this question?

  8. dan815
    • one year ago
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    you can try the rest on your own, its the same method

  9. anonymous
    • one year ago
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    No no it is really the question

  10. ganeshie8
    • one year ago
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    what is the question

  11. ganeshie8
    • one year ago
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    hey is that a new question ?

  12. ganeshie8
    • one year ago
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    3 jackets 6 shirts 4 pants total how many possibilities are there for buying "one" item ?

  13. anonymous
    • one year ago
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    It seems like the first question is a unintelligible. So i posted the last one.

  14. ganeshie8
    • one year ago
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    Yep! one item to choose from 13 items so one of the items can be chosen in 13C1 = 13 ways

  15. ganeshie8
    • one year ago
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    for part b, you need to multiply them : 3C1*6C1*4C1 = 3*6*4 = 72

  16. anonymous
    • one year ago
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    yezzz how about the 4th question

  17. anonymous
    • one year ago
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    12c1?

  18. anonymous
    • one year ago
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    oh its like the fifth question though

  19. ganeshie8
    • one year ago
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    12C1 = 12 for parta looks good

  20. ganeshie8
    • one year ago
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    16 ppl total one class representative can be chosen in 16C1 = 16 ways

  21. ganeshie8
    • one year ago
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    for partb : one male class representative and one female class representative can be chosen in : 8C1*6C1 = 8*6 = 48 ways

  22. anonymous
    • one year ago
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    ?

  23. ganeshie8
    • one year ago
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    nope, your answer for b is wrong

  24. anonymous
    • one year ago
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    is it 14c2?

  25. ganeshie8
    • one year ago
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    First of all, whats your interpretation of the problem ?

  26. ganeshie8
    • one year ago
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    we need to choose two class representative, one from each gender, yes ?

  27. anonymous
    • one year ago
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    yes yes

  28. ganeshie8
    • one year ago
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    whats your answer for part b ?

  29. anonymous
    • one year ago
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    its 48 ways

  30. ganeshie8
    • one year ago
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    good

  31. ganeshie8
    • one year ago
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    for partc, we just need to choose 2 students, gender doesn't matter

  32. ganeshie8
    • one year ago
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    Yes, 2 students can be chosen from 14 students in 14C2 ways.

  33. anonymous
    • one year ago
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    the road

  34. ganeshie8
    • one year ago
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    |dw:1436339681059:dw|

  35. ganeshie8
    • one year ago
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    Suppose A is your home, C is your school and B is an icecream shop on the way

  36. ganeshie8
    • one year ago
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    parta is asking you to find out the number of paths between A and C

  37. anonymous
    • one year ago
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    Okay.. Im following. =)

  38. ganeshie8
    • one year ago
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    Make a guess, how many total paths are there ?

  39. ganeshie8
    • one year ago
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    Nope. Notice that for every path from A to B, there are 4 paths from B to C : |dw:1436340238276:dw|

  40. ganeshie8
    • one year ago
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    since there are 6 paths from A to B, the total number of paths from A to C will be simply 6*4 = 24

  41. ganeshie8
    • one year ago
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    read the question again what do we need to find for parta ?

  42. ganeshie8
    • one year ago
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    it is just asking you to find the number of paths from A to C through B

  43. ganeshie8
    • one year ago
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    there are 24 paths so the answer is 24

  44. ganeshie8
    • one year ago
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    Easy ok

  45. ganeshie8
    • one year ago
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    can you try partb ?

  46. anonymous
    • one year ago
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    part? you mean..

  47. ganeshie8
    • one year ago
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    |dw:1436343105994:dw|

  48. ganeshie8
    • one year ago
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    A to C, there are 6*4 = 24 paths C to A, again there are 4*6 = 24 paths so for a round trip, there are 24*24 distinct paths

  49. anonymous
    • one year ago
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    Thank you so much @ganeshie8 =)

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