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anonymous

  • one year ago

Can anyone give me a "hard" factoring polynomial equation? (If possible, the question can have the combination of factoring techniques.)

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  1. Owlcoffee
    • one year ago
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    Okay, I'll give you a warming up one, factor this: \[6a^2+14b-8-11ab+4b^2-8a\]

  2. anonymous
    • one year ago
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    factor \(x^3 + 7x^2 + 14x +8\)

  3. anonymous
    • one year ago
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    factor \(x^2-8x+17\) without using the quadratic formula or completing the square to find the roots first

  4. anonymous
    • one year ago
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    cough cough \(x^2-2ax+a^2+b^2=(x-(a+bi))(x-(a-bi))\) so \(x^2-8x+17=x^2-8x+16+1=(x-(4+i))(x-(4-i))\)

  5. anonymous
    • one year ago
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    also \(x^3+7x^2+14x+8=x^3+6x^2+8x+x^2+6x+8=(x+1)(x^2+6x+8)\\\quad\quad\quad=(x+1)(x+2)(x+4)\)

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