Joel_the_boss
  • Joel_the_boss
The Math Club is sponsoring a bake sale. If their goal is to raise at least $200, how many pies must they sell at $4.00 each in order to meet that goal? Write, solve, and graph an inequality that represents this situation.
Algebra
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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Joel_the_boss
  • Joel_the_boss
@ganeshie8 Mind helping me? Trying to refresh on basic algebra before i head into trig. Math has never been my strong point. Thanks. :)
Joel_the_boss
  • Joel_the_boss
goal is 200- g pies 4.00 each- 4 number of pies sold- n \(p*n=g\) \(4*n=200\) \(\frac{4}{4}*n= \frac{200}{4}\) \(n=50\) is that correct? @vera_ewing @ganeshie8
butterflydreamer
  • butterflydreamer
weeell firstly, you want to note that we're dealing with an inequality :) "...goal is to raise AT LEAST $200"... so this basically means " \[\ge 200\] Then we know each pie costs $4 So if n = number of pies and we need to raise at least $200, the inequality should be : \[4n \ge 200 \]

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butterflydreamer
  • butterflydreamer
but yes, you're correct in the way you solved it :) At least 50 pies are needed! \[4n \ge 200 \rightarrow n \ge 50 \]
Joel_the_boss
  • Joel_the_boss
Thank you very much. :) @butterflydreamer
butterflydreamer
  • butterflydreamer
nooo problemo ^_^!

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