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Joel_the_boss

  • one year ago

The Math Club is sponsoring a bake sale. If their goal is to raise at least $200, how many pies must they sell at $4.00 each in order to meet that goal? Write, solve, and graph an inequality that represents this situation.

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  1. Joel_the_boss
    • one year ago
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    @ganeshie8 Mind helping me? Trying to refresh on basic algebra before i head into trig. Math has never been my strong point. Thanks. :)

  2. Joel_the_boss
    • one year ago
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    goal is 200- g pies 4.00 each- 4 number of pies sold- n \(p*n=g\) \(4*n=200\) \(\frac{4}{4}*n= \frac{200}{4}\) \(n=50\) is that correct? @vera_ewing @ganeshie8

  3. butterflydreamer
    • one year ago
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    weeell firstly, you want to note that we're dealing with an inequality :) "...goal is to raise AT LEAST $200"... so this basically means " \[\ge 200\] Then we know each pie costs $4 So if n = number of pies and we need to raise at least $200, the inequality should be : \[4n \ge 200 \]

  4. butterflydreamer
    • one year ago
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    but yes, you're correct in the way you solved it :) At least 50 pies are needed! \[4n \ge 200 \rightarrow n \ge 50 \]

  5. Joel_the_boss
    • one year ago
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    Thank you very much. :) @butterflydreamer

  6. butterflydreamer
    • one year ago
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    nooo problemo ^_^!

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