anonymous
  • anonymous
The lines below are perpendicular. If the slope of the green line is 1, what is the slope of the red line ? http://media.apexlearning.com/Images/200706/18/055cb2ff-62ad-426e-a3db-d0871c0ab884.gif m=
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@UsukiDoll
anonymous
  • anonymous
@butterflydreamer
UsukiDoll
  • UsukiDoll
|dw:1436357885165:dw|

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More answers

anonymous
  • anonymous
okay
anonymous
  • anonymous
okay next ..
UsukiDoll
  • UsukiDoll
try an attempt the problem.. either let m_1 = 1 or m_2 = 1 then divide.
anonymous
  • anonymous
m_1=1
UsukiDoll
  • UsukiDoll
|dw:1436358056467:dw| k now what do we need to do next?
anonymous
  • anonymous
? divide ?
UsukiDoll
  • UsukiDoll
yeah
anonymous
  • anonymous
whenever perpendicular, they are both the same.....
anonymous
  • anonymous
-1/-1 ?
anonymous
  • anonymous
just flip the sign
anonymous
  • anonymous
the answer would be 1 ?
UsukiDoll
  • UsukiDoll
@waleedo212 wrong. parallel lines have the same slope
anonymous
  • anonymous
oh okay nvm
UsukiDoll
  • UsukiDoll
@waleedo212 perpendicular lines have different slopes.
UsukiDoll
  • UsukiDoll
\[m_2 = \frac{-1}{1} \]
anonymous
  • anonymous
so divide -1/-1 ?
UsukiDoll
  • UsukiDoll
*points up*
anonymous
  • anonymous
okay
anonymous
  • anonymous
its 1
UsukiDoll
  • UsukiDoll
no!
anonymous
  • anonymous
oh can you help me out on that one .
anonymous
  • anonymous
@UsukiDoll
UsukiDoll
  • UsukiDoll
scroll up to what I've Latex'd
anonymous
  • anonymous
m1xm2=-1
UsukiDoll
  • UsukiDoll
\[m_2 = \frac{-1}{1} \]
anonymous
  • anonymous
okay what would that be ? 1
butterflydreamer
  • butterflydreamer
... -1 divided by 1 = ? 1 divided by 1 = 1 so NEGATIVE 1 divided by 1 is? Anything divided by 1 is the number on top of the fraction
anonymous
  • anonymous
-1
butterflydreamer
  • butterflydreamer
yess
anonymous
  • anonymous
thats the answer then right ?
anonymous
  • anonymous
@butterflydreamer
anonymous
  • anonymous
@UsukiDoll
butterflydreamer
  • butterflydreamer
yes it is. you can always plug it back into the equation \[m_1 \times m_2 = -1 \rightarrow 1 \times -1 = -1 \]

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