## anonymous one year ago The lines below are perpendicular. If the slope of the green line is 1, what is the slope of the red line ? http://media.apexlearning.com/Images/200706/18/055cb2ff-62ad-426e-a3db-d0871c0ab884.gif m=

1. anonymous

@UsukiDoll

2. anonymous

@butterflydreamer

3. UsukiDoll

|dw:1436357885165:dw|

4. anonymous

okay

5. anonymous

okay next ..

6. UsukiDoll

try an attempt the problem.. either let m_1 = 1 or m_2 = 1 then divide.

7. anonymous

m_1=1

8. UsukiDoll

|dw:1436358056467:dw| k now what do we need to do next?

9. anonymous

? divide ?

10. UsukiDoll

yeah

11. anonymous

whenever perpendicular, they are both the same.....

12. anonymous

-1/-1 ?

13. anonymous

just flip the sign

14. anonymous

the answer would be 1 ?

15. UsukiDoll

@waleedo212 wrong. parallel lines have the same slope

16. anonymous

oh okay nvm

17. UsukiDoll

@waleedo212 perpendicular lines have different slopes.

18. UsukiDoll

$m_2 = \frac{-1}{1}$

19. anonymous

so divide -1/-1 ?

20. UsukiDoll

*points up*

21. anonymous

okay

22. anonymous

its 1

23. UsukiDoll

no!

24. anonymous

oh can you help me out on that one .

25. anonymous

@UsukiDoll

26. UsukiDoll

scroll up to what I've Latex'd

27. anonymous

m1xm2=-1

28. UsukiDoll

$m_2 = \frac{-1}{1}$

29. anonymous

okay what would that be ? 1

30. butterflydreamer

... -1 divided by 1 = ? 1 divided by 1 = 1 so NEGATIVE 1 divided by 1 is? Anything divided by 1 is the number on top of the fraction

31. anonymous

-1

32. butterflydreamer

yess

33. anonymous

thats the answer then right ?

34. anonymous

@butterflydreamer

35. anonymous

@UsukiDoll

36. butterflydreamer

yes it is. you can always plug it back into the equation $m_1 \times m_2 = -1 \rightarrow 1 \times -1 = -1$