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anonymous
 one year ago
I need help. I didn't get a good teacher at school so I didn't understand this:
The table shows the outputs y for different inputs x:
Input
(x) 5 6 7 8
Output
(y) 2 5 8 11
Part A: Do the data in this table represent a function? Justify your answer.
Part B: Compare the data in the table with the relation f(x) = 2x + 13. Which relation has a greater value when x = 7?
Part C: Using the relation in Part B, what is the value of x if f(x) = 75?
anonymous
 one year ago
I need help. I didn't get a good teacher at school so I didn't understand this: The table shows the outputs y for different inputs x: Input (x) 5 6 7 8 Output (y) 2 5 8 11 Part A: Do the data in this table represent a function? Justify your answer. Part B: Compare the data in the table with the relation f(x) = 2x + 13. Which relation has a greater value when x = 7? Part C: Using the relation in Part B, what is the value of x if f(x) = 75?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Isn't it when x its own y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean when x has its own y

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0hmm.. well the "formal" defintion of a function is that for every value of "x", there is ONLY one value of "y". So basically, each "x" cannot have more than 1 yvalue. :) So do you think your data is a function?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0excellent :D So now moving onto part b. Look at the function given: \[f(x) = 2x + 13 \] What would f (7) = ? [note: to do this, just plug in x = 7 ... basically replace the x with a 7 ]

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0yyees! :) So for the relation f (x) = 2x + 13 , f (7) = 27 Now looking at your table, what is your "y" when x= 7 ?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0yes, so now can you answer part b? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I can answer C too now

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0alrightiess :)

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0see, it wasn't as bad as you thought :)!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess it wasn't explained well by my algebra teacher. Thanks!

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0you're welcome :)!
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