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Empty
 one year ago
We can define a certain parabola by saying it goes through the points (0,0), (1/2,1), (1,0). I know the answer to this. However I don't understand why this method fails:
Empty
 one year ago
We can define a certain parabola by saying it goes through the points (0,0), (1/2,1), (1,0). I know the answer to this. However I don't understand why this method fails:

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Empty
 one year ago
Best ResponseYou've already chosen the best response.0\[\left[ \begin{array}c 0 & 0 & 0\\1/4 & 1/2 & 1\\1 & 1 & 1\\\end{array} \right]\left[ \begin{array}c a\\ b\\ c\\\end{array} \right] =\left[ \begin{array}c 0\\ 1\\ 0\\\end{array} \right]\] I can't invert this matrix!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i can't make head or tails of what that is supposed to do

Empty
 one year ago
Best ResponseYou've already chosen the best response.0Waittt.t.... I just realized my problem

Empty
 one year ago
Best ResponseYou've already chosen the best response.0I put a full 0 vector in that top column, the last one should be a 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is way way too much work to solve this very easy question, right?

Empty
 one year ago
Best ResponseYou've already chosen the best response.0Ahhh so it just represents the system of equations from plugging in the points to: \(ax^2+bx+c = f(x) \) Yeah you're right the best way I found to do this is we are given two roots so we write: f(x) = k(x0)(x1) and plug in the point f(1/2)=1 to solve for k.
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