## anonymous one year ago Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is$3. Sal made a profit of \$1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work Describe how you would graph this line using the slope-intercept methodBe sure to write usi

1. anonymous

$2x+3y=1470$ The first thing you need to do is rearrange the formula so only the Y is on the left hand side .All you need to do is do the opposite to what is given

2. anonymous

So in this case you would start by subtracting 2x from the left hand side so ,so you hav eto minus 2x from both sides It should look like this $3y = -2x + 1470$

3. anonymous

Then you still have 3y instead of y so you need to divide both sides by 3 . So you need to divide 3x by 3,-2x by 3 and 1470 by 3 It should look like this $\frac{ 3y }{ 3}=\frac{ -2x }{ 3 }+\frac{ 1470 }{ 3 }$

4. anonymous

The equation should look like this$y= -\frac{ 2 }{ 3 }x +490$

5. anonymous

Now to graph this line you can find the x and y intercepts Let start with the y intercept To do this all you need to do is substitute the x for 0 to find y

6. anonymous

y int x=0 $y=(-\frac{ 2 }{ 3 }\times0)+490$ y=490

7. anonymous

x intercept can be found when y = 0 $0=-\frac{ 2 }{ 3}x+ 490$ Then solve it like a linear equation So 0-490 and then divide this by -2/3 It shoudld equal 735

8. anonymous

To graph this so can see that you need a big scale because of the numbers so a graph like the one below should suffice

9. anonymous

The scale for the graph should be 1cm for 100 and then just plot the points On the y axis,plot it at 490 and on the x axis ,plot it at 735 and then draw a line between the two

10. anonymous

|dw:1436366501473:dw|

11. anonymous

Hope that helps @ripnana813