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ok then ' \[f(2)=3\times 2^2+2\] what is that number?
I got 68
think you did the "order 'o operations" wrong square first, then multiply
How do I square?
\(\sf 2^2 \rightarrow 2 \times 2\)
how do you square a number? multiply it by itself so \[2^2=2\times 2\]
so it'd be f(2)=3×2x2+2?
yes what is \[ 3\times 2\times 2+2\]?
right now hold on to that number
\[g(x)=x-8\] what is \[g(2)\]?
g(2) = x - 8?
hmmm i see you are a bit confused as to how to evaluate a function
\[g(x)=x-8\\ g(\spadesuit)=\spadesuit-8\\ g(\xi)=\xi -8\]
so how do you find \(g(2)\)? where you see an \(x\) replace it by a \(2\)
g(2) = 2 - 8? The other two functions have clovers and & signs in them, not sure if it's meant to be there.
So what's the next step?
-6, if i'm solving from left to right
g(2) = -6?
yes it is \(-6\) no matter what you do
final step \[f\times g(2)=f(2)\times g(2)=14\times (-6)\]
so the final answer woulds be -84?
Thanks :)) Could you help me with a few more?
lol sure we can at least do one more
Gaming systems are on sale for 20% off the original price (g), which can be expressed with the function p(g) = 0.8g. Local taxes are an additional 12% of the discounted price (p), which can be expressed with the function c(p) = 1.12p. Using this information, which of the following represents the final price of a gaming system with the discount and taxes applied? c(p) + p(g) = 1.92g c[p(g)] = 0.896g g[c(p)] = 1.92p c(p) ⋅ p(g) = 0.896pg
This seems like an easy one, it's just the trouble of setting up the function I guess
it is easy it is the last one
How did you get that?
lets do it with an item that cost $100
first take the 20% discount, multiply \[100\times .8=80\]
so it is $80 before the tax then put in the tax get \[80\times 1.12=89.6\]
what did we do? first multiply by \(.8\) then multiply by \(1.12\)
ohh hold the phone for a second
i see what they want you to say, they want you to pick B
Oooh so it's B?
first do \(p\) then do \(c\) it is \[c(p(g))\]
which is kind of silly since you can do it just by multiplying, but whatever pick B
Alright that's what I was thinking too haha, thank you. Couple more :D?
Or would you rather me open a new question to give you another best response?