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anonymous

  • one year ago

The average (arithmetic mean) bowling score of n bowlers is 160. The average of these n scores together with a score of 170 is 161. What is the number of bowlers, n?

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  1. welshfella
    • one year ago
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    total scores for n bowlers = 160n total scores + 170 = 160n + 170 average of these is (160n + 170) / (n+1)

  2. anonymous
    • one year ago
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    ok so this is what i have so far

  3. welshfella
    • one year ago
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    equate this to 161 and solve for n

  4. anonymous
    • one year ago
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    |dw:1436379175410:dw|

  5. welshfella
    • one year ago
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    no - there is no need to introduce another variable x check out my post

  6. anonymous
    • one year ago
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    why? we dont know how much the other bowlers had though...

  7. welshfella
    • one year ago
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    we know that there are n bowlers and the average of their scores is 160 so the total scores = 160 8 n. We don't know the individual scores of each bowler but we don't need to . Average = total / n , so total = n * average

  8. anonymous
    • one year ago
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    oh okay

  9. welshfella
    • one year ago
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    * that is 160* n

  10. welshfella
    • one year ago
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    so we have the equation 160n + 170 ---------- = 161 n + 1 - we divide by n+1 because there is 1 more bowler with a score of 170

  11. anonymous
    • one year ago
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    ouuuuuuuuuu i got it now

  12. welshfella
    • one year ago
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    cross multiply 160n + 700 = 161n + 161 can you solve for n?

  13. anonymous
    • one year ago
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    9

  14. welshfella
    • one year ago
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    right

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