anonymous
  • anonymous
The average (arithmetic mean) bowling score of n bowlers is 160. The average of these n scores together with a score of 170 is 161. What is the number of bowlers, n?
Mathematics
chestercat
  • chestercat
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welshfella
  • welshfella
total scores for n bowlers = 160n total scores + 170 = 160n + 170 average of these is (160n + 170) / (n+1)
anonymous
  • anonymous
ok so this is what i have so far
welshfella
  • welshfella
equate this to 161 and solve for n

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anonymous
  • anonymous
|dw:1436379175410:dw|
welshfella
  • welshfella
no - there is no need to introduce another variable x check out my post
anonymous
  • anonymous
why? we dont know how much the other bowlers had though...
welshfella
  • welshfella
we know that there are n bowlers and the average of their scores is 160 so the total scores = 160 8 n. We don't know the individual scores of each bowler but we don't need to . Average = total / n , so total = n * average
anonymous
  • anonymous
oh okay
welshfella
  • welshfella
* that is 160* n
welshfella
  • welshfella
so we have the equation 160n + 170 ---------- = 161 n + 1 - we divide by n+1 because there is 1 more bowler with a score of 170
anonymous
  • anonymous
ouuuuuuuuuu i got it now
welshfella
  • welshfella
cross multiply 160n + 700 = 161n + 161 can you solve for n?
anonymous
  • anonymous
9
welshfella
  • welshfella
right

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