Please Help !! Find the area of the triangle.

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Please Help !! Find the area of the triangle.

Mathematics
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Please post the triangle :)
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Use A=hbb the formula to find the area 2

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here are my choices A. 68.4 square units B. 75.3 square units C. 84.5 square units D. 136.7 square units
We have to use trig, right?
how do i plug them in?
yes
Ok, let me post the formula for finding it.
H= Height B= Base
\(\sf\Large Area= ab\frac{sin \gamma}{2}\) where \(\sf\gamma\) is the angle in between sides a and b
@erbear2763 This question is too complex for that basic geometry formula.
wow im confused
|dw:1436383580173:dw|
|dw:1436383588085:dw|
we have to find r?
It's actually gamma but yes
alpha, beta, and gamma are what we use to call angles in trig...
oh
so the sum of all the angles in a triangle is?
so what would the answer be?
*facepalm*
We do \(\sf\color{red}{not}\) give you answers, we \(\bf guide\) you to the answer.
hahah @AbdullahM its just im on a timed test
|dw:1436383860348:dw|
Wow, now you're even cheating.
\[\sin 63 =\frac{AH}{13}\] you can find AH from here
Please read our Anti-Cheating policy. http://pages.citebite.com/a4o3b6r4a2tjy
nah .... i can use resources man :) not cheating
why u gotta put me on blast like that man? @AbdullahM
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you can find AH with respect to sin(63) then by using \[13^2+AH^2=DH^2\\DH=\frac{DF}{2}\] so you can easily find area
CAN YOU HELP ME SOLVE IT?
AH=13 sin 63=11.58 \[13^2=DH^2+11.58^2\\\] DH=5.9 |dw:1436390071459:dw| so area=DF *AH /2 =11.58 *5.9*2/2 =63.34
@e.mccormick user was asking a test question...

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