Please Help !!
Find the area of the triangle.

- anonymous

Please Help !!
Find the area of the triangle.

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- AbdullahM

Please post the triangle :)

- anonymous

##### 1 Attachment

- anonymous

Use A=hbb the formula to find the area
2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

here are my choices
A.
68.4 square units
B.
75.3 square units
C.
84.5 square units
D.
136.7 square units

- AbdullahM

We have to use trig, right?

- anonymous

how do i plug them in?

- anonymous

yes

- AbdullahM

Ok, let me post the formula for finding it.

- anonymous

H= Height
B= Base

- AbdullahM

\(\sf\Large Area= ab\frac{sin \gamma}{2}\)
where \(\sf\gamma\) is the angle in between sides a and b

- AbdullahM

@erbear2763 This question is too complex for that basic geometry formula.

- anonymous

wow im confused

- AbdullahM

|dw:1436383580173:dw|

- AbdullahM

|dw:1436383588085:dw|

- anonymous

we have to find r?

- AbdullahM

It's actually gamma but yes

- AbdullahM

alpha, beta, and gamma are what we use to call angles in trig...

- anonymous

oh

- AbdullahM

so the sum of all the angles in a triangle is?

- anonymous

so what would the answer be?

- AbdullahM

*facepalm*

- AbdullahM

We do \(\sf\color{red}{not}\) give you answers, we \(\bf guide\) you to the answer.

- anonymous

hahah @AbdullahM its just im on a timed test

- amoodarya

|dw:1436383860348:dw|

- AbdullahM

Wow, now you're even cheating.

- amoodarya

\[\sin 63 =\frac{AH}{13}\]
you can find AH from here

- AbdullahM

Please read our Anti-Cheating policy.
http://pages.citebite.com/a4o3b6r4a2tjy

- anonymous

nah .... i can use resources man :) not cheating

- anonymous

why u gotta put me on blast like that man? @AbdullahM

- AbdullahM

"By using the OpenStudy Site or Service, you agree to abide by OpenStudy’s Anti-cheating Policy and to also comply with copyright laws and the academic policies or honor codes of your school and course, and to report violations promptly to us.
Posting questions from tests, exams or other third party content may be an infringement of copyrights of the owner of the posted content. In most cases, asking for help on an exam or test, or helping someone during their test or exam, will be considered cheating by the institution or by OpenStudy. OpenStudy reserves the right to remove such content and/or suspend, ban or otherwise remove Users from the system who are suspected of cheating. If you feel there is an error, You may email contact@openstudy with an explanation but You acknowledge that the determination to remove content or suspend, ban or otherwise remove a User from the system is within the sole discretion of Company.
By using the OpenStudy Site or Service, you acknowledge that OpenStudy cooperates fully with schools, colleges and other educational institutions (together “Schools”) and reserves the right to disclose User information to a School if there is an allegation by that School of cheating or violation of the School’s academic policies.
Openstudy.com will take swift action against anyone found misusing the community’s Site or Service. In addition to refunding any membership fee, we will ban Users who cheat from the Site and Service permanently."

- amoodarya

you can find AH with respect to sin(63)
then by using
\[13^2+AH^2=DH^2\\DH=\frac{DF}{2}\]
so you can easily find area

- anonymous

CAN YOU HELP ME SOLVE IT?

- amoodarya

AH=13 sin 63=11.58
\[13^2=DH^2+11.58^2\\\]
DH=5.9
|dw:1436390071459:dw|
so
area=DF *AH /2 =11.58 *5.9*2/2 =63.34

- AbdullahM

@e.mccormick user was asking a test question...

Looking for something else?

Not the answer you are looking for? Search for more explanations.