anonymous
  • anonymous
Please Help !! Find the area of the triangle.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AbdullahM
  • AbdullahM
Please post the triangle :)
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Use A=hbb the formula to find the area 2

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More answers

anonymous
  • anonymous
here are my choices A. 68.4 square units B. 75.3 square units C. 84.5 square units D. 136.7 square units
AbdullahM
  • AbdullahM
We have to use trig, right?
anonymous
  • anonymous
how do i plug them in?
anonymous
  • anonymous
yes
AbdullahM
  • AbdullahM
Ok, let me post the formula for finding it.
anonymous
  • anonymous
H= Height B= Base
AbdullahM
  • AbdullahM
\(\sf\Large Area= ab\frac{sin \gamma}{2}\) where \(\sf\gamma\) is the angle in between sides a and b
AbdullahM
  • AbdullahM
@erbear2763 This question is too complex for that basic geometry formula.
anonymous
  • anonymous
wow im confused
AbdullahM
  • AbdullahM
|dw:1436383580173:dw|
AbdullahM
  • AbdullahM
|dw:1436383588085:dw|
anonymous
  • anonymous
we have to find r?
AbdullahM
  • AbdullahM
It's actually gamma but yes
AbdullahM
  • AbdullahM
alpha, beta, and gamma are what we use to call angles in trig...
anonymous
  • anonymous
oh
AbdullahM
  • AbdullahM
so the sum of all the angles in a triangle is?
anonymous
  • anonymous
so what would the answer be?
AbdullahM
  • AbdullahM
*facepalm*
AbdullahM
  • AbdullahM
We do \(\sf\color{red}{not}\) give you answers, we \(\bf guide\) you to the answer.
anonymous
  • anonymous
hahah @AbdullahM its just im on a timed test
amoodarya
  • amoodarya
|dw:1436383860348:dw|
AbdullahM
  • AbdullahM
Wow, now you're even cheating.
amoodarya
  • amoodarya
\[\sin 63 =\frac{AH}{13}\] you can find AH from here
AbdullahM
  • AbdullahM
Please read our Anti-Cheating policy. http://pages.citebite.com/a4o3b6r4a2tjy
anonymous
  • anonymous
nah .... i can use resources man :) not cheating
anonymous
  • anonymous
why u gotta put me on blast like that man? @AbdullahM
AbdullahM
  • AbdullahM
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amoodarya
  • amoodarya
you can find AH with respect to sin(63) then by using \[13^2+AH^2=DH^2\\DH=\frac{DF}{2}\] so you can easily find area
anonymous
  • anonymous
CAN YOU HELP ME SOLVE IT?
amoodarya
  • amoodarya
AH=13 sin 63=11.58 \[13^2=DH^2+11.58^2\\\] DH=5.9 |dw:1436390071459:dw| so area=DF *AH /2 =11.58 *5.9*2/2 =63.34
AbdullahM
  • AbdullahM
@e.mccormick user was asking a test question...

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