Please Help !!
Find the area of the triangle.

- anonymous

Please Help !!
Find the area of the triangle.

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- chestercat

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- AbdullahM

Please post the triangle :)

- anonymous

##### 1 Attachment

- anonymous

Use A=hbb the formula to find the area
2

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## More answers

- anonymous

here are my choices
A.
68.4 square units
B.
75.3 square units
C.
84.5 square units
D.
136.7 square units

- AbdullahM

We have to use trig, right?

- anonymous

how do i plug them in?

- anonymous

yes

- AbdullahM

Ok, let me post the formula for finding it.

- anonymous

H= Height
B= Base

- AbdullahM

\(\sf\Large Area= ab\frac{sin \gamma}{2}\)
where \(\sf\gamma\) is the angle in between sides a and b

- AbdullahM

@erbear2763 This question is too complex for that basic geometry formula.

- anonymous

wow im confused

- AbdullahM

|dw:1436383580173:dw|

- AbdullahM

|dw:1436383588085:dw|

- anonymous

we have to find r?

- AbdullahM

It's actually gamma but yes

- AbdullahM

alpha, beta, and gamma are what we use to call angles in trig...

- anonymous

oh

- AbdullahM

so the sum of all the angles in a triangle is?

- anonymous

so what would the answer be?

- AbdullahM

*facepalm*

- AbdullahM

We do \(\sf\color{red}{not}\) give you answers, we \(\bf guide\) you to the answer.

- anonymous

hahah @AbdullahM its just im on a timed test

- amoodarya

|dw:1436383860348:dw|

- AbdullahM

Wow, now you're even cheating.

- amoodarya

\[\sin 63 =\frac{AH}{13}\]
you can find AH from here

- AbdullahM

Please read our Anti-Cheating policy.
http://pages.citebite.com/a4o3b6r4a2tjy

- anonymous

nah .... i can use resources man :) not cheating

- anonymous

why u gotta put me on blast like that man? @AbdullahM

- AbdullahM

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- amoodarya

you can find AH with respect to sin(63)
then by using
\[13^2+AH^2=DH^2\\DH=\frac{DF}{2}\]
so you can easily find area

- anonymous

CAN YOU HELP ME SOLVE IT?

- amoodarya

AH=13 sin 63=11.58
\[13^2=DH^2+11.58^2\\\]
DH=5.9
|dw:1436390071459:dw|
so
area=DF *AH /2 =11.58 *5.9*2/2 =63.34

- AbdullahM

@e.mccormick user was asking a test question...

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