1. AbdullahM

2. anonymous

3. anonymous

Use A=hbb the formula to find the area 2

4. anonymous

here are my choices A. 68.4 square units B. 75.3 square units C. 84.5 square units D. 136.7 square units

5. AbdullahM

We have to use trig, right?

6. anonymous

how do i plug them in?

7. anonymous

yes

8. AbdullahM

Ok, let me post the formula for finding it.

9. anonymous

H= Height B= Base

10. AbdullahM

$$\sf\Large Area= ab\frac{sin \gamma}{2}$$ where $$\sf\gamma$$ is the angle in between sides a and b

11. AbdullahM

@erbear2763 This question is too complex for that basic geometry formula.

12. anonymous

wow im confused

13. AbdullahM

|dw:1436383580173:dw|

14. AbdullahM

|dw:1436383588085:dw|

15. anonymous

we have to find r?

16. AbdullahM

It's actually gamma but yes

17. AbdullahM

alpha, beta, and gamma are what we use to call angles in trig...

18. anonymous

oh

19. AbdullahM

so the sum of all the angles in a triangle is?

20. anonymous

so what would the answer be?

21. AbdullahM

*facepalm*

22. AbdullahM

We do $$\sf\color{red}{not}$$ give you answers, we $$\bf guide$$ you to the answer.

23. anonymous

hahah @AbdullahM its just im on a timed test

24. amoodarya

|dw:1436383860348:dw|

25. AbdullahM

Wow, now you're even cheating.

26. amoodarya

$\sin 63 =\frac{AH}{13}$ you can find AH from here

27. AbdullahM

28. anonymous

nah .... i can use resources man :) not cheating

29. anonymous

why u gotta put me on blast like that man? @AbdullahM

30. AbdullahM

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31. amoodarya

you can find AH with respect to sin(63) then by using $13^2+AH^2=DH^2\\DH=\frac{DF}{2}$ so you can easily find area

32. anonymous

CAN YOU HELP ME SOLVE IT?

33. amoodarya

AH=13 sin 63=11.58 $13^2=DH^2+11.58^2\\$ DH=5.9 |dw:1436390071459:dw| so area=DF *AH /2 =11.58 *5.9*2/2 =63.34

34. AbdullahM

@e.mccormick user was asking a test question...