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anonymous

  • one year ago

Please Help !! Find the area of the triangle.

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  1. AbdullahM
    • one year ago
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    Please post the triangle :)

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    Use A=hbb the formula to find the area 2

  4. anonymous
    • one year ago
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    here are my choices A. 68.4 square units B. 75.3 square units C. 84.5 square units D. 136.7 square units

  5. AbdullahM
    • one year ago
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    We have to use trig, right?

  6. anonymous
    • one year ago
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    how do i plug them in?

  7. anonymous
    • one year ago
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    yes

  8. AbdullahM
    • one year ago
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    Ok, let me post the formula for finding it.

  9. anonymous
    • one year ago
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    H= Height B= Base

  10. AbdullahM
    • one year ago
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    \(\sf\Large Area= ab\frac{sin \gamma}{2}\) where \(\sf\gamma\) is the angle in between sides a and b

  11. AbdullahM
    • one year ago
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    @erbear2763 This question is too complex for that basic geometry formula.

  12. anonymous
    • one year ago
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    wow im confused

  13. AbdullahM
    • one year ago
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    |dw:1436383580173:dw|

  14. AbdullahM
    • one year ago
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    |dw:1436383588085:dw|

  15. anonymous
    • one year ago
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    we have to find r?

  16. AbdullahM
    • one year ago
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    It's actually gamma but yes

  17. AbdullahM
    • one year ago
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    alpha, beta, and gamma are what we use to call angles in trig...

  18. anonymous
    • one year ago
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    oh

  19. AbdullahM
    • one year ago
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    so the sum of all the angles in a triangle is?

  20. anonymous
    • one year ago
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    so what would the answer be?

  21. AbdullahM
    • one year ago
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    *facepalm*

  22. AbdullahM
    • one year ago
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    We do \(\sf\color{red}{not}\) give you answers, we \(\bf guide\) you to the answer.

  23. anonymous
    • one year ago
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    hahah @AbdullahM its just im on a timed test

  24. amoodarya
    • one year ago
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    |dw:1436383860348:dw|

  25. AbdullahM
    • one year ago
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    Wow, now you're even cheating.

  26. amoodarya
    • one year ago
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    \[\sin 63 =\frac{AH}{13}\] you can find AH from here

  27. AbdullahM
    • one year ago
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    Please read our Anti-Cheating policy. http://pages.citebite.com/a4o3b6r4a2tjy

  28. anonymous
    • one year ago
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    nah .... i can use resources man :) not cheating

  29. anonymous
    • one year ago
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    why u gotta put me on blast like that man? @AbdullahM

  30. AbdullahM
    • one year ago
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    "By using the OpenStudy Site or Service, you agree to abide by OpenStudy’s Anti-cheating Policy and to also comply with copyright laws and the academic policies or honor codes of your school and course, and to report violations promptly to us. Posting questions from tests, exams or other third party content may be an infringement of copyrights of the owner of the posted content. In most cases, asking for help on an exam or test, or helping someone during their test or exam, will be considered cheating by the institution or by OpenStudy. OpenStudy reserves the right to remove such content and/or suspend, ban or otherwise remove Users from the system who are suspected of cheating. If you feel there is an error, You may email contact@openstudy with an explanation but You acknowledge that the determination to remove content or suspend, ban or otherwise remove a User from the system is within the sole discretion of Company. By using the OpenStudy Site or Service, you acknowledge that OpenStudy cooperates fully with schools, colleges and other educational institutions (together “Schools”) and reserves the right to disclose User information to a School if there is an allegation by that School of cheating or violation of the School’s academic policies. Openstudy.com will take swift action against anyone found misusing the community’s Site or Service. In addition to refunding any membership fee, we will ban Users who cheat from the Site and Service permanently."

  31. amoodarya
    • one year ago
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    you can find AH with respect to sin(63) then by using \[13^2+AH^2=DH^2\\DH=\frac{DF}{2}\] so you can easily find area

  32. anonymous
    • one year ago
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    CAN YOU HELP ME SOLVE IT?

  33. amoodarya
    • one year ago
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    AH=13 sin 63=11.58 \[13^2=DH^2+11.58^2\\\] DH=5.9 |dw:1436390071459:dw| so area=DF *AH /2 =11.58 *5.9*2/2 =63.34

  34. AbdullahM
    • one year ago
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    @e.mccormick user was asking a test question...

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