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anonymous
 one year ago
How do I find the radius of a circle with a center at (1, 2), which also passes through point (0,2)?
anonymous
 one year ago
How do I find the radius of a circle with a center at (1, 2), which also passes through point (0,2)?

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amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[(xx_c)^2+(yy_c)^2=r^2\\center=(1,2)\\so\\(x+1)^2+(y+2)^2=r^2\\\] the circle passes through (0,2) dw:1436385033207:dw so check the point in equation to find r can you go on ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@amoodarya I'm still a little confused. Could you explain further?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The previous post used the standard form of a circle at center (h ,k) Let h=xc let k= yc then you have a point (0,2) (0,2) (x+1)^2 + (y+2)^2 = r^2 (0+1)^2 + (2+2)^2 = r^2 1+4 = r^2 5= r^2 \[r=\sqrt{5}\]
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