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anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 3) and a directrix at y = 3.
anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 3) and a directrix at y = 3.

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phi
 one year ago
Best ResponseYou've already chosen the best response.1it helps to plot the directrix and the focus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well I know the vertex is (0,0)

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes the vertex is half way between them, so at (0,0) people label the vertex (h,k)

phi
 one year ago
Best ResponseYou've already chosen the best response.1and we know the parabola "surrounds" the focus so it looks (something) like dw:1436389795339:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1(yk)= a(xh)^2 with (h,k)= 0 and a will be negative y = ax^2 we need to find a

phi
 one year ago
Best ResponseYou've already chosen the best response.1I think people write it as \[ 4 p y = x^2 \] and p is the distance from the vertex to the focus (or vertex to the directrix) p=3 and negative because it's facing down 12y= x^2 so \[ y= \frac{1}{12} x^2 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks. I understand. I have a few more questions but i'll post new forms. Thanks again, @phi
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