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anonymous

  • one year ago

I need somebody to walk me through this, I understand the just of it. PLease Help! Medal and Fan!

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    @peachpi

  3. anonymous
    • one year ago
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    @AllAmericanViking

  4. anonymous
    • one year ago
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  5. anonymous
    • one year ago
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  6. anonymous
    • one year ago
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    @nincompoop

  7. anonymous
    • one year ago
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    What is the question? I might be able to help you.

  8. anonymous
    • one year ago
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    The function H(t) = -16t2 + vt + s shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

  9. anonymous
    • one year ago
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    Is this FLVS?

  10. anonymous
    • one year ago
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    Yep!

  11. anonymous
    • one year ago
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    Algebra?

  12. anonymous
    • one year ago
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    Algebra 1 semester 2, just this and im done the whole thing

  13. anonymous
    • one year ago
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    did you plug in the numbers to create the equation for A?

  14. anonymous
    • one year ago
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    i tried to but didnt quite understand

  15. anonymous
    • one year ago
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    Ok I just finished it yesterday. Maybe I can see if I had it too

  16. anonymous
    • one year ago
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    this is what i got H(t) = -16(96)^2 + 80(96) + 96

  17. anonymous
    • one year ago
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    \(H(t)=-16t^2+vt+s\) is the basic equation. You need to replace the v with the velocity they gave you, and replace the s with the initial height. t is the variable, so it stays the same.

  18. anonymous
    • one year ago
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    all you need to do is change v to 80 and s to 96

  19. anonymous
    • one year ago
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    so the velocity is 80 fps and the height is 96 but whats the time?

  20. anonymous
    • one year ago
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    ?

  21. anonymous
    • one year ago
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    what about t?

  22. anonymous
    • one year ago
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    time is the independent variable. the projectile has a different height for different values of time. It's 96 in the beginning and then goes up and comes back down

  23. anonymous
    • one year ago
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    i actually do need time to type, you know?

  24. anonymous
    • one year ago
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    sorry, okay s it would be H(t) = -16t^2 + 80t + 96?

  25. anonymous
    • one year ago
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    yes

  26. anonymous
    • one year ago
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    Sweet! now could you help with b?

  27. anonymous
    • one year ago
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    would you solve for t?

  28. anonymous
    • one year ago
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    Yes, for B, the height's going to be the y-coordinate of the vertex using the equation from a.

  29. anonymous
    • one year ago
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    \[t=-\frac{ b }{ 2a }\] Look familiar?

  30. anonymous
    • one year ago
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    then once you have that t, plug it in to get the height

  31. anonymous
    • one year ago
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    Yes, okay soi got 5/2?

  32. anonymous
    • one year ago
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    that's the right time. now put it in for t in the equation from A

  33. anonymous
    • one year ago
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    \[-16(5/2)^2+80(5/2)+96\]

  34. anonymous
    • one year ago
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    oh okay, and then solve?

  35. anonymous
    • one year ago
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    yes

  36. anonymous
    • one year ago
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    i got 196?

  37. anonymous
    • one year ago
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    yes that's right

  38. anonymous
    • one year ago
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    C?

  39. anonymous
    • one year ago
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    for c, create a table for the values 0 through 5 and plug them into both equations

  40. anonymous
    • one year ago
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    You're looking for the t where you get the same (or pretty close) H for both equations

  41. anonymous
    • one year ago
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    okay let me see

  42. anonymous
    • one year ago
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    is it possible to solve algebraicly without a table?

  43. anonymous
    • one year ago
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    yes, but you probably haven't done it in algebra I. |dw:1436390010929:dw|

  44. anonymous
    • one year ago
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    you'd set the equations equal to each other then solve for t -16t^2 + 80t + 96 = 31+32.2t

  45. anonymous
    • one year ago
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    it's a standard quadratic equation, so maybe you've done that

  46. anonymous
    • one year ago
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    my bad didnt mean to type that

  47. anonymous
    • one year ago
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    both aanswers are rounded but i got t = -1, t = 4

  48. anonymous
    • one year ago
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    you want to go with 4 because time has to be positive

  49. anonymous
    • one year ago
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    okay, so thats the answer for c?

  50. anonymous
    • one year ago
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    yes

  51. anonymous
    • one year ago
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    for D, 4 seconds is after the max height at 2.5 seconds, so it's got to be on the way down

  52. anonymous
    • one year ago
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    okay, thank you so much! that really helped a lot :)

  53. anonymous
    • one year ago
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    you're welcome

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