anonymous
  • anonymous
I need somebody to walk me through this, I understand the just of it. PLease Help! Medal and Fan!
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
What is the question? I might be able to help you.
anonymous
  • anonymous
The function H(t) = -16t2 + vt + s shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)
anonymous
  • anonymous
Is this FLVS?
anonymous
  • anonymous
Yep!
anonymous
  • anonymous
Algebra?
anonymous
  • anonymous
Algebra 1 semester 2, just this and im done the whole thing
anonymous
  • anonymous
did you plug in the numbers to create the equation for A?
anonymous
  • anonymous
i tried to but didnt quite understand
anonymous
  • anonymous
Ok I just finished it yesterday. Maybe I can see if I had it too
anonymous
  • anonymous
this is what i got H(t) = -16(96)^2 + 80(96) + 96
anonymous
  • anonymous
\(H(t)=-16t^2+vt+s\) is the basic equation. You need to replace the v with the velocity they gave you, and replace the s with the initial height. t is the variable, so it stays the same.
anonymous
  • anonymous
all you need to do is change v to 80 and s to 96
anonymous
  • anonymous
so the velocity is 80 fps and the height is 96 but whats the time?
anonymous
  • anonymous
?
anonymous
  • anonymous
what about t?
anonymous
  • anonymous
time is the independent variable. the projectile has a different height for different values of time. It's 96 in the beginning and then goes up and comes back down
anonymous
  • anonymous
i actually do need time to type, you know?
anonymous
  • anonymous
sorry, okay s it would be H(t) = -16t^2 + 80t + 96?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Sweet! now could you help with b?
anonymous
  • anonymous
would you solve for t?
anonymous
  • anonymous
Yes, for B, the height's going to be the y-coordinate of the vertex using the equation from a.
anonymous
  • anonymous
\[t=-\frac{ b }{ 2a }\] Look familiar?
anonymous
  • anonymous
then once you have that t, plug it in to get the height
anonymous
  • anonymous
Yes, okay soi got 5/2?
anonymous
  • anonymous
that's the right time. now put it in for t in the equation from A
anonymous
  • anonymous
\[-16(5/2)^2+80(5/2)+96\]
anonymous
  • anonymous
oh okay, and then solve?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i got 196?
anonymous
  • anonymous
yes that's right
anonymous
  • anonymous
C?
anonymous
  • anonymous
for c, create a table for the values 0 through 5 and plug them into both equations
anonymous
  • anonymous
You're looking for the t where you get the same (or pretty close) H for both equations
anonymous
  • anonymous
okay let me see
anonymous
  • anonymous
is it possible to solve algebraicly without a table?
anonymous
  • anonymous
yes, but you probably haven't done it in algebra I. |dw:1436390010929:dw|
anonymous
  • anonymous
you'd set the equations equal to each other then solve for t -16t^2 + 80t + 96 = 31+32.2t
anonymous
  • anonymous
it's a standard quadratic equation, so maybe you've done that
anonymous
  • anonymous
my bad didnt mean to type that
anonymous
  • anonymous
both aanswers are rounded but i got t = -1, t = 4
anonymous
  • anonymous
you want to go with 4 because time has to be positive
anonymous
  • anonymous
okay, so thats the answer for c?
anonymous
  • anonymous
yes
anonymous
  • anonymous
for D, 4 seconds is after the max height at 2.5 seconds, so it's got to be on the way down
anonymous
  • anonymous
okay, thank you so much! that really helped a lot :)
anonymous
  • anonymous
you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.