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anonymous
 one year ago
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
anonymous
 one year ago
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

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phi
 one year ago
Best ResponseYou've already chosen the best response.1the center is the average of the vertices

phi
 one year ago
Best ResponseYou've already chosen the best response.1the vertices are on the yaxis, so the hyperbola looks like a frown/smile combo that means the "y' goes first in the standard equation \[ \frac{(yk)^2}{a^2} \frac{(xh)^2}{b^2}=1\] a is the distance from the center to the focus "c" is the distance from the center to the vertex we use a and c to find b a^2 + b^2 = c^2 we already know (h,k) is (0,0)

phi
 one year ago
Best ResponseYou've already chosen the best response.1oops, got that swapped: a is the distance from the center to the vertex "c" is the distance from the center to the focus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so a is 6 and c is 9

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, but in the equation you use a^2 = 36 and c^2=81 what is b^2 ?

phi
 one year ago
Best ResponseYou've already chosen the best response.1a^2 + b^2 = c^2 36 + b^2 = 81

phi
 one year ago
Best ResponseYou've already chosen the best response.1now fill in the numbers to get the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks. I still have a few more
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