anonymous
  • anonymous
Evaluate |c 2 + b 2|, given a = 5, b = -3, and c = -2.
Mathematics
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anonymous
  • anonymous
Evaluate |c 2 + b 2|, given a = 5, b = -3, and c = -2.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
help?
anonymous
  • anonymous
answer is 10 positive 10 you want an explanation?
anonymous
  • anonymous
@.Gjallarhorn. yes please

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anonymous
  • anonymous
so since c=-2, you multiply -2 and 2 together. what do you get?
anonymous
  • anonymous
-4? @.Gjallarhorn.
anonymous
  • anonymous
right now leave that off to the side and lets go to the other one
anonymous
  • anonymous
since b=-3 you multiply -3 and 2 together and you get?
anonymous
  • anonymous
-6
anonymous
  • anonymous
good. now you gotta add both your results. so -4 + -6 =?
anonymous
  • anonymous
making it positive 10
anonymous
  • anonymous
good try but no. -4+ -6= -10
anonymous
  • anonymous
but thats not our final answer. so you see how the equation has a line like this? >> |
anonymous
  • anonymous
on both sides?
anonymous
  • anonymous
yea
anonymous
  • anonymous
that means whatever you get inside those lines, is measured as a distance from 0
anonymous
  • anonymous
how many units away it is from 0.
anonymous
  • anonymous
oh i thought it was the negatives canceiling each other out >.<
anonymous
  • anonymous
so in |-6| -6 is 6 units away from 0. so your answer would be six in a question like this
anonymous
  • anonymous
oh okay
anonymous
  • anonymous
thats just an example
anonymous
  • anonymous
so how many units is -10 away from 0?
anonymous
  • anonymous
10 units
anonymous
  • anonymous
right. so these are always positive. 10 is your answer . good job
anonymous
  • anonymous
thanks
jdoe0001
  • jdoe0001
hmm \(\large |c^2 + b^2|\qquad \begin{cases} a=5\\b=-3\\c=-2 \end{cases}\qquad ?\)
anonymous
  • anonymous
no prob

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