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anonymous

  • one year ago

Evaluate |c 2 + b 2|, given a = 5, b = -3, and c = -2.

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  1. anonymous
    • one year ago
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    help?

  2. anonymous
    • one year ago
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    answer is 10 positive 10 you want an explanation?

  3. anonymous
    • one year ago
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    @.Gjallarhorn. yes please

  4. anonymous
    • one year ago
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    so since c=-2, you multiply -2 and 2 together. what do you get?

  5. anonymous
    • one year ago
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    -4? @.Gjallarhorn.

  6. anonymous
    • one year ago
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    right now leave that off to the side and lets go to the other one

  7. anonymous
    • one year ago
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    since b=-3 you multiply -3 and 2 together and you get?

  8. anonymous
    • one year ago
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    -6

  9. anonymous
    • one year ago
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    good. now you gotta add both your results. so -4 + -6 =?

  10. anonymous
    • one year ago
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    making it positive 10

  11. anonymous
    • one year ago
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    good try but no. -4+ -6= -10

  12. anonymous
    • one year ago
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    but thats not our final answer. so you see how the equation has a line like this? >> |

  13. anonymous
    • one year ago
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    on both sides?

  14. anonymous
    • one year ago
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    yea

  15. anonymous
    • one year ago
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    that means whatever you get inside those lines, is measured as a distance from 0

  16. anonymous
    • one year ago
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    how many units away it is from 0.

  17. anonymous
    • one year ago
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    oh i thought it was the negatives canceiling each other out >.<

  18. anonymous
    • one year ago
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    so in |-6| -6 is 6 units away from 0. so your answer would be six in a question like this

  19. anonymous
    • one year ago
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    oh okay

  20. anonymous
    • one year ago
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    thats just an example

  21. anonymous
    • one year ago
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    so how many units is -10 away from 0?

  22. anonymous
    • one year ago
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    10 units

  23. anonymous
    • one year ago
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    right. so these are always positive. 10 is your answer . good job

  24. anonymous
    • one year ago
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    thanks

  25. jdoe0001
    • one year ago
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    hmm \(\large |c^2 + b^2|\qquad \begin{cases} a=5\\b=-3\\c=-2 \end{cases}\qquad ?\)

  26. anonymous
    • one year ago
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    no prob

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