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Look at your reaction first Ask yourself if this is balanced you cannot do any calculation without balancing your reaction ensuring that the number of atoms is the same on each side otherwise you'll be we on every time.
Zn + 2HCl ---> ZnCl2 + H2 So we look at our reaction and its balanced. The question asks how many grams of zinc will react with 5.4L of 2.8M HCl Now ask, there's a hint in this: M = molarity which is the number of moles of solute/liter of solvent. So M = mol/liter We multiply 5.4L•(2.8mol/L) and when we do this the L•(1/L) cancel and were left with moles so that would be 15.4 moL. Of HCL
alright i see. is just so confusing im doing terrible in he class lol ill try my best to ollow along
Now we have 15.4 moles of HCl We must now find the number of moles of Zinc that we need to completely ready with HCl, and to do that we must look at the molar ratio. It's 2:1 So 15.4 mol ZnCl x (1 Zn/2ZnCL) = 7.7 moles of Zn . Notice what I did here I multiplied by the. Molar ratio and the number of moles canceled out for the reactant I didn't want and I was left with the reactant I wanted in this case Zn
but how do you find out the molar ration for like another problem?
Now we have 7.7 moles of Zn To find the number of grams this is easy. All we do is the following, Moles• (grams/mol) = grams 7.7 moles Zn•(65.4 Zn g/mol) = 504.6 grams of Zn
okay i see
Ok so if I gave you the haber process N2 + 3H2 ---> 2NH3 And I said what is the molar ratio of nitrogen to hydrogen what would it be?
You must always look at the coefficients in front of the reactants and products and then use their ratio to find the number of moles you need.
is the ration 1:2 because 3N / 6H = 1/2?
Try again Look at the coefficients in front of the reactant there is a 3 in front of hydrogen gas, 1 in front of nitrogen gas. And a 2 in front of NH3. N2(g) 3H2(g)
The molar ratio of nitrogen gas to hydrogen would be 1N/3H2 or 1:3 What about ammonia to nitrogen?
i dont know.. How would i find ammonias?