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- anonymous

How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.
Zn (s) + 2 HCl (aq) yields ZnCl2 (aq) + H2 (g)
the thing is i dont understand chemistry at all... if someone could walk me through in depth and how to do it and stuff

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- anonymous

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- Photon336

Look at your reaction first
Ask yourself if this is balanced you cannot do any calculation without balancing your reaction ensuring that the number of atoms is the same on each side otherwise you'll be we on every time.

- Photon336

Zn + 2HCl ---> ZnCl2 + H2
So we look at our reaction and its balanced.
The question asks how many grams of zinc will react with 5.4L of 2.8M HCl
Now ask, there's a hint in this: M = molarity which is the number of moles of solute/liter of solvent.
So M = mol/liter
We multiply 5.4L•(2.8mol/L) and when we do this the L•(1/L) cancel and were left with moles so that would be 15.4 moL. Of HCL

- anonymous

alright i see. is just so confusing im doing terrible in he class lol ill try my best to ollow along

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- Photon336

Now we have 15.4 moles of HCl
We must now find the number of moles of Zinc that we need to completely ready with HCl, and to do that we must look at the molar ratio.
It's 2:1
So 15.4 mol ZnCl x (1 Zn/2ZnCL) = 7.7 moles of Zn .
Notice what I did here I multiplied by the. Molar ratio and the number of moles canceled out for the reactant I didn't want and I was left with the reactant I wanted in this case Zn

- anonymous

but how do you find out the molar ration for like another problem?

- Photon336

Now we have 7.7 moles of Zn
To find the number of grams this is easy.
All we do is the following,
Moles• (grams/mol) = grams
7.7 moles Zn•(65.4 Zn g/mol) = 504.6 grams of Zn

- anonymous

okay i see

- Photon336

Ok so if I gave you the haber process
N2 + 3H2 ---> 2NH3
And I said what is the molar ratio of nitrogen to hydrogen what would it be?

- Photon336

You must always look at the coefficients in front of the reactants and products and then use their ratio to find the number of moles you need.

- anonymous

is the ration 1:2 because 3N / 6H = 1/2?

- Photon336

Try again
Look at the coefficients in front of the reactant there is a 3 in front of hydrogen gas, 1 in front of nitrogen gas. And a 2 in front of NH3.
N2(g)
3H2(g)

- Photon336

The molar ratio of nitrogen gas to hydrogen would be 1N/3H2 or 1:3
What about ammonia to nitrogen?

- anonymous

i dont know.. How would i find ammonias?

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