anonymous
  • anonymous
Find the magnitude & direction of the vector JK given points J(1,0) & K(-2,3).
Mathematics
katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
First we need to find the vector in form Subtract the corresponding coordinates (tail - head) x = -2 - 1 = -3 y = 3 - 0 = 3 the vector JK is <-3, 3> now you will use the formula sqrt(x^2 + y^2) to get the magnitude to get the direction, use arctan(y/x). The angle is in Q2, so you'll have to add 180 degrees
jdoe0001
  • jdoe0001
\(\large u=\qquad \begin{cases} magnitude\implies \sqrt{a^2+b^2}\\ direction\implies tan^{-1}\left( \frac{b}{a} \right) \end{cases}\)
anonymous
  • anonymous
wait im kinda confused

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jim_thompson5910
  • jim_thompson5910
where are you stuck?
anonymous
  • anonymous
nevermind i got it thanks

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