anonymous one year ago Find the magnitude & direction of the vector JK given points J(1,0) & K(-2,3).

1. jim_thompson5910

First we need to find the vector in <x,y> form Subtract the corresponding coordinates (tail - head) x = -2 - 1 = -3 y = 3 - 0 = 3 the vector JK is <-3, 3> now you will use the formula sqrt(x^2 + y^2) to get the magnitude to get the direction, use arctan(y/x). The angle is in Q2, so you'll have to add 180 degrees

2. jdoe0001

$$\large u=<a,b>\qquad \begin{cases} magnitude\implies \sqrt{a^2+b^2}\\ direction\implies tan^{-1}\left( \frac{b}{a} \right) \end{cases}$$

3. anonymous

wait im kinda confused

4. jim_thompson5910

where are you stuck?

5. anonymous

nevermind i got it thanks