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anonymous
 one year ago
Freddie is at chess practice waiting on his opponent's next move. He notices that the 4inchlong minute hand is rotating around the clock and marking off time like degrees on a unit circle.
Part 1: How many radians does the minute hand move from 3:35 to 3:55? (Hint: Find the number of degrees per minute first.)
Part 2: How far does the tip of the minute hand travel during that time?
Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches?
Part 4: What is the coordinate points associated with this radian measure?
anonymous
 one year ago
Freddie is at chess practice waiting on his opponent's next move. He notices that the 4inchlong minute hand is rotating around the clock and marking off time like degrees on a unit circle. Part 1: How many radians does the minute hand move from 3:35 to 3:55? (Hint: Find the number of degrees per minute first.) Part 2: How far does the tip of the minute hand travel during that time? Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches? Part 4: What is the coordinate points associated with this radian measure?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First step is to find how many degrees there are per minute. 60 minutes to 360 degrees. So how many degrees per minute?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06 degrees per minute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right. And we're trying to figure out how many degrees there are for 20 minutes. \[\large \sf 20 \times 6 =120\] so we're solving for 120 degrees. Do you know what 120 degrees looks like in radian form?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right. So part 1 done. Next it to find the distance the tip traveled. For this we'll use the formula \[\large \sf Arc~=~r \times \theta\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol i dont get his part sry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well wanna use a different formula? We're looking for the distance the tip traveled. In other words, the arc it traveled around the circumference of the clock. dw:1436398679715:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And we'll use the formula \[\large \sf Arc~=~r \times \theta\] to find the arc length.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is the radian style formula by the way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait whats the unknowns

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So \(\large \sf \theta=\frac{2\pi}{3}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And r is stated in the top part of your question. Yeah, r is 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \sf \theta=\frac{2\pi}{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \sf Arc~=~4 \times \frac{2\pi}{3}\]\[\large \sf Arc~=~\frac{8\pi}{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yea sry i multiplied wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways, Part 3 uses the same formula. The only difference is what we're solving for. \[\large \sf 3\pi~=~4 \times \theta\]
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