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Summersnow8
 one year ago
Did I solve this correctly?
Find the x and ycomponent (round to the nearest 10th) of a vector with magnitude 15 m and direction 105°.
Sin 105 = X/15 → X = 15 * Sin 105 = 14.5
Cos 105 = y/15 → Y= 15 * Cos 105 = 3.9
Summersnow8
 one year ago
Did I solve this correctly? Find the x and ycomponent (round to the nearest 10th) of a vector with magnitude 15 m and direction 105°. Sin 105 = X/15 → X = 15 * Sin 105 = 14.5 Cos 105 = y/15 → Y= 15 * Cos 105 = 3.9

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Hmm, well I would assume dw:1436397571213:dw

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.1wouldn't x be a negative number because it is in the 2nd quadrant instead of y?

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.1then how come that is not what I got then....?

radar
 one year ago
Best ResponseYou've already chosen the best response.0Don't you have your X and Y mixed up......isn't the Y = 15 Sin theta

radar
 one year ago
Best ResponseYou've already chosen the best response.0Yes x is Cos and Y is Sin

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.1my bad, I got mixed up, so it's 3.9, 14.5

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436398054020:dw

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1And yes with your correct rounding

Summersnow8
 one year ago
Best ResponseYou've already chosen the best response.1so i would put a  sign in front of the 3.9?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Right. Your 'x' component is the 3.9 and the 'y' component is the 14.5
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