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Summersnow8

  • one year ago

Did I solve this correctly? Find the x- and y-component (round to the nearest 10th) of a vector with magnitude 15 m and direction 105°. Sin 105 = X/15 → X = 15 * Sin 105 = 14.5 Cos 105 = y/15 → Y= 15 * Cos 105 = -3.9

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  1. johnweldon1993
    • one year ago
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    Hmm, well I would assume |dw:1436397571213:dw|

  2. Summersnow8
    • one year ago
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    wouldn't x be a negative number because it is in the 2nd quadrant instead of y?

  3. Summersnow8
    • one year ago
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    then how come that is not what I got then....?

  4. radar
    • one year ago
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    Don't you have your X and Y mixed up......isn't the Y = 15 Sin theta

  5. Summersnow8
    • one year ago
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    no X is Cos

  6. radar
    • one year ago
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    Yes x is Cos and Y is Sin

  7. Summersnow8
    • one year ago
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    my bad, I got mixed up, so it's -3.9, 14.5

  8. johnweldon1993
    • one year ago
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    |dw:1436398054020:dw|

  9. johnweldon1993
    • one year ago
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    And yes with your correct rounding

  10. Summersnow8
    • one year ago
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    so i would put a - sign in front of the 3.9?

  11. johnweldon1993
    • one year ago
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    Right. Your 'x' component is the -3.9 and the 'y' component is the 14.5

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