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anonymous
 one year ago
3.Substitute your birthday into the equation Square root of the quantity x minus y + m = d, where y is the last two digits of your birth year, m is the month, and d is the day. If you were born on 7/10/1856 like Nikola Tesla, your equation would be Square root of the quantity x minus 56 + 7 = 10. Solve for x and identify if it is an extraneous solution. My birthday is 06/06/1998
who ever answers this I will give a medal to.
anonymous
 one year ago
3.Substitute your birthday into the equation Square root of the quantity x minus y + m = d, where y is the last two digits of your birth year, m is the month, and d is the day. If you were born on 7/10/1856 like Nikola Tesla, your equation would be Square root of the quantity x minus 56 + 7 = 10. Solve for x and identify if it is an extraneous solution. My birthday is 06/06/1998 who ever answers this I will give a medal to.

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chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.2Dang my birthday is May 9th 1997! This seems a little tricky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know I tried asking my teacher but he wouldn't help me ..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What's stopping you from doing what the example showed you?

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.2So I got \[\sqrt{x98} +6=6\]

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.2But I don't know if the question is asking for this: \[\sqrt{x98} +6=6\] or this: \[\sqrt{x98+6}=6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got sqrt x98 +6=6 I just don't understand how to solve the equation

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Ok, but answer what chris has asked you, please specify your equation.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Is it \[\sqrt{x98}+6=6 ~~~~ \text{or}~~~\sqrt{x98+6}=6\]...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x98} +6=6\] is what I got

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Ok good, so now you want to look for the extraneous solution

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0So we want to solve for x right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes wouldn't we square the x98 to get rid of the square root?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Right! See you know this stuff :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0First lets simplify it a bit, move the 6 on the right

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Then we'll take the square root

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we take the square root of the 6 right?

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.2Yes, so your left with x98 + 6 = 6

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Well I meant, lets make it easier on ourselves by doing this \[\sqrt{x98}6=6 \implies \sqrt{x98} = 12\]

chrisdbest
 one year ago
Best ResponseYou've already chosen the best response.2You know what to do from here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes thank you guys so much for the help!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Np, everything make sense now?
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