## anonymous one year ago 3.Substitute your birthday into the equation Square root of the quantity x minus y + m = d, where y is the last two digits of your birth year, m is the month, and d is the day. If you were born on 7/10/1856 like Nikola Tesla, your equation would be Square root of the quantity x minus 56 + 7 = 10. Solve for x and identify if it is an extraneous solution. My birthday is 06/06/1998 who ever answers this I will give a medal to.

1. chrisdbest

Dang my birthday is May 9th 1997! This seems a little tricky

2. anonymous

I know I tried asking my teacher but he wouldn't help me .-.

3. Astrophysics

What's stopping you from doing what the example showed you?

4. chrisdbest

So I got $\sqrt{x-98} +6=6$

5. chrisdbest

But I don't know if the question is asking for this: $\sqrt{x-98} +6=6$ or this: $\sqrt{x-98+6}=6$

6. anonymous

I got sqrt x-98 +6=6 I just don't understand how to solve the equation

7. Astrophysics

8. Astrophysics

Is it $\sqrt{x-98}+6=6 ~~~~ \text{or}~~~\sqrt{x-98+6}=6$...

9. anonymous

$\sqrt{x-98} +6=6$ is what I got

10. Astrophysics

Ok good, so now you want to look for the extraneous solution

11. Astrophysics

So we want to solve for x right?

12. anonymous

Yes wouldn't we square the x-98 to get rid of the square root?

13. Astrophysics

Right! See you know this stuff :)

14. chrisdbest

And what's next?

15. Astrophysics

First lets simplify it a bit, move the 6 on the right

16. Astrophysics

Then we'll take the square root

17. anonymous

So we take the square root of the 6 right?

18. chrisdbest

Yes, so your left with x-98 + 6 = 6

19. Astrophysics

Well I meant, lets make it easier on ourselves by doing this $\sqrt{x-98}-6=6 \implies \sqrt{x-98} = 12$

20. chrisdbest

You know what to do from here?

21. anonymous

Yes thank you guys so much for the help!

22. Astrophysics

Np, everything make sense now?