Explain why the following is true: If C is the center of the circle, triangle BCD is an equilateral triangle.

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Explain why the following is true: If C is the center of the circle, triangle BCD is an equilateral triangle.

Mathematics
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well, assuming that the triangle BCD is inscribed in the circle like so: |dw:1436400969882:dw|
|dw:1436401004361:dw|
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|dw:1436401334084:dw|
(bad drawing, apologies) EC and AD intersect, giving us the vertical angle 60 on both sides
Yeah that's what I have so far. I just need to find a way to say the angle CBD and angle CDB are 60 degrees too
split the 60 degree angle on the right side into 30 and 30
|dw:1436401484203:dw|
giving us |dw:1436401524183:dw|
basically, what I did was draw a straight line down from D to C, resulting in two right triangles, each with an angle of 30 and 90, and the remaining angle is 60 because 30+60+90 = 180 hopefully that wasn't too confusing to understand D:
It wasn't thanks!

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