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jackellyn

  • one year ago

Explain why the following is true: If C is the center of the circle, triangle BCD is an equilateral triangle.

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  1. Vocaloid
    • one year ago
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    well, assuming that the triangle BCD is inscribed in the circle like so: |dw:1436400969882:dw|

  2. Vocaloid
    • one year ago
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    |dw:1436401004361:dw|

  3. jackellyn
    • one year ago
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  4. Vocaloid
    • one year ago
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    |dw:1436401334084:dw|

  5. Vocaloid
    • one year ago
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    (bad drawing, apologies) EC and AD intersect, giving us the vertical angle 60 on both sides

  6. jackellyn
    • one year ago
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    Yeah that's what I have so far. I just need to find a way to say the angle CBD and angle CDB are 60 degrees too

  7. Vocaloid
    • one year ago
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    split the 60 degree angle on the right side into 30 and 30

  8. Vocaloid
    • one year ago
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    |dw:1436401484203:dw|

  9. Vocaloid
    • one year ago
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    giving us |dw:1436401524183:dw|

  10. Vocaloid
    • one year ago
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    basically, what I did was draw a straight line down from D to C, resulting in two right triangles, each with an angle of 30 and 90, and the remaining angle is 60 because 30+60+90 = 180 hopefully that wasn't too confusing to understand D:

  11. jackellyn
    • one year ago
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    It wasn't thanks!

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