Explain why the following is true: If C is the center of the circle, triangle BCD is an equilateral triangle.
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well, assuming that the triangle BCD is inscribed in the circle like so:
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(bad drawing, apologies) EC and AD intersect, giving us the vertical angle 60 on both sides
Yeah that's what I have so far. I just need to find a way to say the angle CBD and angle CDB are 60 degrees too
split the 60 degree angle on the right side into 30 and 30
basically, what I did was draw a straight line down from D to C, resulting in two right triangles, each with an angle of 30 and 90, and the remaining angle is 60 because 30+60+90 = 180
hopefully that wasn't too confusing to understand D: