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anonymous
 one year ago
Find the Quotient of 20x^2y88xy/4xy
anonymous
 one year ago
Find the Quotient of 20x^2y88xy/4xy

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1The problem is this, right? \[\Large \frac{20x^2y88xy}{4xy}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1we can factor out 4xy from the numerator \[\Large \frac{20x^2y88xy}{4xy} = \frac{4xy(5x+22)}{4xy} \] what comes next?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm having a very hard time understanding even from the beginning, if you can i would love for you to help explain it to me.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well I factored out 4xy because that's what is in the denominator I want to cancel out the denominator

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1did you learn about factoring yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i believe so but I'm not positive

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the idea of factoring is to rewrite a number or expression as a product of two smaller things

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ex: 27 = 9*3 16 = 8*2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could possibly be 22x^2y^2+20x^2y

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the awnser i asked my mom and she said she thinks that is what it is

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1have you learned about the distributive property?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that not with (X)^Y

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's something like 2*(x+y) = 2*x + 2*y

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so when I factored back up at the top, I used the distributive property (in reverse)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you have 2*x + 2*y you can factor out 2 to get 2*(x+y)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1same idea with your problem, but I pulled out 4xy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay im some what following lol

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it turns out that 4xy is a common factor of 20x^2y and 88xy

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436404481447:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436404502668:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436404585098:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436404604417:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436404621090:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why would it not be 8xy?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.18xy? where do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04xy on both sides of the equation

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'm not sure what you mean exactly, but this is what the full step by step picture looks like \[\Large \frac{20x^2y88xy}{4xy} = \frac{4xy(5x+22)}{4xy} \] \[\Large \frac{20x^2y88xy}{4xy} = \frac{\cancel{4xy}(5x+22)}{\cancel{4xy}} \] \[\Large \frac{20x^2y88xy}{4xy} = 5x+22 \] so the original expression simplifies to 5x+22

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so they two cancel one another out correct?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah they divide to 1 and go away effectively

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i understand that
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