anonymous
  • anonymous
Find the Quotient of 20x^2y-88xy/-4xy
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
The problem is this, right? \[\Large \frac{20x^2y-88xy}{-4xy}\]
anonymous
  • anonymous
Yes
jim_thompson5910
  • jim_thompson5910
we can factor out -4xy from the numerator \[\Large \frac{20x^2y-88xy}{-4xy} = \frac{-4xy(-5x+22)}{-4xy} \] what comes next?

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anonymous
  • anonymous
I'm having a very hard time understanding even from the beginning, if you can i would love for you to help explain it to me.
jim_thompson5910
  • jim_thompson5910
well I factored out -4xy because that's what is in the denominator I want to cancel out the denominator
jim_thompson5910
  • jim_thompson5910
did you learn about factoring yet?
anonymous
  • anonymous
i believe so but I'm not positive
jim_thompson5910
  • jim_thompson5910
the idea of factoring is to rewrite a number or expression as a product of two smaller things
jim_thompson5910
  • jim_thompson5910
ex: 27 = 9*3 16 = 8*2
anonymous
  • anonymous
could possibly be 22x^2y^2+20x^2y
jim_thompson5910
  • jim_thompson5910
what do you mean?
anonymous
  • anonymous
for the awnser i asked my mom and she said she thinks that is what it is
jim_thompson5910
  • jim_thompson5910
have you learned about the distributive property?
anonymous
  • anonymous
is that not with (X)^Y
jim_thompson5910
  • jim_thompson5910
it's something like 2*(x+y) = 2*x + 2*y
anonymous
  • anonymous
yeah i have
jim_thompson5910
  • jim_thompson5910
so when I factored back up at the top, I used the distributive property (in reverse)
jim_thompson5910
  • jim_thompson5910
if you have 2*x + 2*y you can factor out 2 to get 2*(x+y)
jim_thompson5910
  • jim_thompson5910
same idea with your problem, but I pulled out -4xy
anonymous
  • anonymous
okay im some what following lol
jim_thompson5910
  • jim_thompson5910
it turns out that -4xy is a common factor of 20x^2y and -88xy
jim_thompson5910
  • jim_thompson5910
|dw:1436404481447:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1436404502668:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1436404585098:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1436404604417:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1436404621090:dw|
anonymous
  • anonymous
why would it not be -8xy?
jim_thompson5910
  • jim_thompson5910
-8xy? where do you mean?
anonymous
  • anonymous
-4xy on both sides of the equation
jim_thompson5910
  • jim_thompson5910
I'm not sure what you mean exactly, but this is what the full step by step picture looks like \[\Large \frac{20x^2y-88xy}{-4xy} = \frac{-4xy(-5x+22)}{-4xy} \] \[\Large \frac{20x^2y-88xy}{-4xy} = \frac{\cancel{-4xy}(-5x+22)}{\cancel{-4xy}} \] \[\Large \frac{20x^2y-88xy}{-4xy} = -5x+22 \] so the original expression simplifies to -5x+22
anonymous
  • anonymous
okay so they two cancel one another out correct?
jim_thompson5910
  • jim_thompson5910
yeah they divide to 1 and go away effectively
anonymous
  • anonymous
okay i understand that

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