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anonymous
 one year ago
f(x) = 2e^3x + 1
Find the inverse f^1(x). Can anyone help?
anonymous
 one year ago
f(x) = 2e^3x + 1 Find the inverse f^1(x). Can anyone help?

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jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Set it equal to y. Switch the x and the y, solve for y.

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5y=2x^3+1 x=2y^3+1 Solve for y.

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Did you get the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my calculator is messing up, can you walk me through it pls. @jackellyn

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5so to solve for y you need to perform reverse operations. If we have x=2e^3y +1 What do we need to do first to get y alone?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0subtract 3y on both sides @jackellyn i think

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Well the 3y is part of the exponent so we can't get rid of it just yet. First we need to get rid of the +1 and move it to the other side so do we add it to both sides or subtract it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0subtract it @jackellyn

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Right so we have x1= 2e^3y Now we need to get rid of the 2 in front of the e^3y. What do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jakellyn if thats correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jackellyn you there

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Yes, divide so then we have (x1)/2=e^3y Do you remember the opposite operation of e?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't recall @jackellyn

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5You need to take the natural log of both sides to get rid of the e and stay only with 3y. ln (x1/2)=ln e^3y ln (x1/2)=3y Solve for y.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y =\frac{ x }{ 3}\frac{ 1 }{ 6 }\] is that correct? @jackellyn

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so is this the inverse for \[f ^{1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jackellyn idk if you saw my replies^^^^

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5Sorry, I didnt. You can't get rid of the ln. It stays all together and then you can divide the 3. So \[y=\frac{(\ln \frac{ x1 }{ 2 }) }{ 3 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thats the inverse of \[f ^{1}(x)\]

jackellyn
 one year ago
Best ResponseYou've already chosen the best response.5It is the inverse of f(x). \[f ^{1}(x)\] is the notation for inverse.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i understand now thx a lot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jackellyn one more question what is the inverse
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