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its part of my geometry course @LegendarySadist trig is one of the sections lol

*algebra 2

use a co-function identity

for example, recall one of the co-function identities is:
\[\cos(u)=\sin(\frac{\pi}{2}-u)\]

wow that really confused me

why does it confuse you?

because this stuff is like another language to me

but why does the identity confuse you?

is it because you never seen it?

kinda this is my first time learning this

|dw:1436410191044:dw|

could you find cos(theta)
and sin(90-theta) using this right triangle ?

|dw:1436410266489:dw|

since I used 90 deg there

but we can do the same thing for radians
and say
\[\sin(\frac{\pi}{2}-\theta)=\cos(\theta)\]

would the answer be 13?

so what would that make the answer be?

set the insides equal

and solve for x

\[3x+13=\frac{\pi}{2}-4x \]

I still don't get my answer

oh so its 11

your answer should have pi in it somewhere so 11 isn't the answer

or a answer in this case

the options are 11 -13 13 and 0

so what would the answer come out to be

have you tried pluggin in the choices as I suggested above?

i only have 1 minute until i have to submit it

what is sin(3*11 deg+13 deg)=?

give you a hint 3*11+13=33+13=46
and guess what 90-46 is?

good luck