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@AG23 not a option
Expand the brackets. What do you get? Then, collect like terms. I'll give you a similar example. 4(x-y) + (x-2y) = 4x - 4y + x - 2y = 4x + x - 4y - 2y = 5x - 6y Try using a similar approach for your question
i dont no how to do the whole adding and subtracting letters thing without the little guide
please refrain from giving direct answers as it is against OpenStudy's Code of Conduct. The purpose of this site is to guide the user to answering their question.
to expand the brackets and to distribute means the same thing. multiply the term outside by each term inside follow the example given by @ Tommynaut above
You can add and subtract letters (also known as pronumerals or variables) that are the same. For example, I can't do anything with x + 2y, because the letters are different! How about 2x + 3x? The letters are the same! So, we just add the COEFFICIENTS (the numbers that are next to and multiplied with the letters) together. So, for 2x + 3x, we do 2+3 = 5. So 2x + 3x = 5x. Remember to keep the x!
So basically 6(x+y). Is the same as (6x)+(6y) Do you get it now?
Simplifying 6(x + y) + (x + -1y) (x * 6 + y * 6) + (x + -1y) (6x + 6y) + (x + -1y) Remove parenthesis around (x + -1y) 6x + 6y + x + -1y Reorder the terms: 6x + x + 6y + -1y Combine like terms: 6x + x = 7x 7x + 6y + -1y Combine like terms: 6y + -1y = 5y 7x + 5y So like this? @UsukiDoll sorry Im new
It's sort of like saying, let x mean balls. I have 2 balls, and another 3 balls. That means I have 2 balls + 3 balls, which is 5 balls.
there is no other number for me to do that with..... (ex: the whole (x-y) thing is confusing because i dont no what to do about it)
@Tommynaut i do understand what you are doing though
@Frascamr it's ok... but please refer to this website for more information about the code of conduct. http://openstudy.com/code-of-conduct As for the explanation. I think it's ok, but a bit too much. try step by step :)
when you don't see the number it is understood the number is 1
Imagine that there's a 1 outside (x-y), because really, 1 is multiplied by everything all the time. The number 6? Yeah, that's just 6 times 1. So (x-y) can be thought of as 1(x-y), which, if you expand the brackets, just gives you x - y
i got 5x + 4Y which i no is wrong because it isnt a option
Ok, let's go through step-by-step. So we start with... 6(x + y) + (x - y). Now what? Let's expand the brackets. Do you know how to do that?
yea you put it as 6x - 6y + 1x - 1y ....... i think
everything is right so far except the sign for 6(x+y)
Almost! But it's 6x + 6y, not 6x - 6y, where did the negative sign come from?
typos can happen XD
i had wrote it on the original problem then marked it out and then did it again on the second one >.<
6x + 6y + x - y . now combine like terms
oh now i see the answer well at least half 7x unless 7x is the answer
you can rearrange the equation to make the computation easier 6x + x + 6y - y .
nooooooooooo... we just combine like terms. we can't combine x and y together
so just 12?
oh i no what you meant
6x + x + 6y - y I'm going to factor out the variables to make it easier x(6+1)+y(6-1)
6x + 6y
7x + 7y
almost... x is correct y isn't what's 6-1
yes so we have 5y so our answer is 7x+5y