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anonymous

  • one year ago

What is the wavelength in Ångstroms of radiation used by an x-ray technician, with a frequency of 6.00 x 10^18 s-1? Please help me solve this problem by providing steps/work. The answer is .50X10^3 A. Thank you so much for helping.

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  1. nincompoop
    • one year ago
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    were you given a formula in your lesson or class about wavelength, energy, etc?

  2. anonymous
    • one year ago
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    i believe it was C/F and C=3.0* 10^8

  3. Astrophysics
    • one year ago
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    \[v = \lambda f\] is what you need, and yes x - rays go at the speed of light, so we are solving for \[\lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3 \times 10^8 m/s }{ 6 \times 10^{18} \frac{ 1 }{ s } } = 5 \times 10^{-11} m\] are you sure it's 10^18 Angstrom?

  4. Astrophysics
    • one year ago
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    I meant Hz

  5. Astrophysics
    • one year ago
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    To convert to angstrom just use \[1 ~ angstrom = 10^{-10}m\]

  6. Astrophysics
    • one year ago
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    Are you there @gabz12

  7. anonymous
    • one year ago
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    i keep getting the 5*10^11 but the answer is 0.5 A

  8. Astrophysics
    • one year ago
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    Are all the numbers in your question right? Your answer should be same as mine then but it's in meters, we have to convert it to angstrom as I just told you...

  9. Astrophysics
    • one year ago
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    Yo nin do this

  10. Astrophysics
    • one year ago
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    When I convert it to angstrom I get 0.5 A

  11. nincompoop
    • one year ago
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    I would solve it first using meters and then convert in the end

  12. Astrophysics
    • one year ago
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    Aahah that's what I did

  13. Astrophysics
    • one year ago
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    Oh I see he said the answer was 0.5 A

  14. Astrophysics
    • one year ago
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    Ok so we have to convert it to angstrom \[\frac{ 5 \times 10^{-11}m }{ 10^{-10} m} \times 1 A = 0.5 A\] b00m

  15. Astrophysics
    • one year ago
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    do you understand @gabz12

  16. nincompoop
    • one year ago
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    \(\huge \lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3.0 \times 10^8 ms^{-1} }{ 6.00 \times 10^{18} s^{-1} } \times \frac{1.0 A}{10^{-10}m}\) see how the units can be beautifully canceled out whole numbers simplified

  17. anonymous
    • one year ago
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    that formula should be provided right? ok i get it now thank you!

  18. Astrophysics
    • one year ago
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    An easy way to think of this formula is, think about the units, notice how velocity is m/s, wavelength is m, and if you get frequency don't worry just think about the units and get 1/s. Another way notice how this formula IS exactly like \[v = \frac{ d }{ t }\] so that should give you a clue on what's going on.

  19. nincompoop
    • one year ago
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    OH ahaha wow I effed that one up

  20. nincompoop
    • one year ago
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    let me remove it

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