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anonymous
 one year ago
What is the wavelength in Ångstroms of radiation used by an xray technician, with a frequency of 6.00 x 10^18 s1?
Please help me solve this problem by providing steps/work. The answer is .50X10^3 A.
Thank you so much for helping.
anonymous
 one year ago
What is the wavelength in Ångstroms of radiation used by an xray technician, with a frequency of 6.00 x 10^18 s1? Please help me solve this problem by providing steps/work. The answer is .50X10^3 A. Thank you so much for helping.

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nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2were you given a formula in your lesson or class about wavelength, energy, etc?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i believe it was C/F and C=3.0* 10^8

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[v = \lambda f\] is what you need, and yes x  rays go at the speed of light, so we are solving for \[\lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3 \times 10^8 m/s }{ 6 \times 10^{18} \frac{ 1 }{ s } } = 5 \times 10^{11} m\] are you sure it's 10^18 Angstrom?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2To convert to angstrom just use \[1 ~ angstrom = 10^{10}m\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Are you there @gabz12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i keep getting the 5*10^11 but the answer is 0.5 A

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Are all the numbers in your question right? Your answer should be same as mine then but it's in meters, we have to convert it to angstrom as I just told you...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2When I convert it to angstrom I get 0.5 A

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2I would solve it first using meters and then convert in the end

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Aahah that's what I did

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Oh I see he said the answer was 0.5 A

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ok so we have to convert it to angstrom \[\frac{ 5 \times 10^{11}m }{ 10^{10} m} \times 1 A = 0.5 A\] b00m

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2do you understand @gabz12

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2\(\huge \lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3.0 \times 10^8 ms^{1} }{ 6.00 \times 10^{18} s^{1} } \times \frac{1.0 A}{10^{10}m}\) see how the units can be beautifully canceled out whole numbers simplified

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that formula should be provided right? ok i get it now thank you!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2An easy way to think of this formula is, think about the units, notice how velocity is m/s, wavelength is m, and if you get frequency don't worry just think about the units and get 1/s. Another way notice how this formula IS exactly like \[v = \frac{ d }{ t }\] so that should give you a clue on what's going on.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2OH ahaha wow I effed that one up
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