## anonymous one year ago What is the wavelength in Ångstroms of radiation used by an x-ray technician, with a frequency of 6.00 x 10^18 s-1? Please help me solve this problem by providing steps/work. The answer is .50X10^3 A. Thank you so much for helping.

1. nincompoop

were you given a formula in your lesson or class about wavelength, energy, etc?

2. anonymous

i believe it was C/F and C=3.0* 10^8

3. Astrophysics

$v = \lambda f$ is what you need, and yes x - rays go at the speed of light, so we are solving for $\lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3 \times 10^8 m/s }{ 6 \times 10^{18} \frac{ 1 }{ s } } = 5 \times 10^{-11} m$ are you sure it's 10^18 Angstrom?

4. Astrophysics

I meant Hz

5. Astrophysics

To convert to angstrom just use $1 ~ angstrom = 10^{-10}m$

6. Astrophysics

Are you there @gabz12

7. anonymous

i keep getting the 5*10^11 but the answer is 0.5 A

8. Astrophysics

Are all the numbers in your question right? Your answer should be same as mine then but it's in meters, we have to convert it to angstrom as I just told you...

9. Astrophysics

Yo nin do this

10. Astrophysics

When I convert it to angstrom I get 0.5 A

11. nincompoop

I would solve it first using meters and then convert in the end

12. Astrophysics

Aahah that's what I did

13. Astrophysics

Oh I see he said the answer was 0.5 A

14. Astrophysics

Ok so we have to convert it to angstrom $\frac{ 5 \times 10^{-11}m }{ 10^{-10} m} \times 1 A = 0.5 A$ b00m

15. Astrophysics

do you understand @gabz12

16. nincompoop

$$\huge \lambda = \frac{ v }{ f } = \frac{ c }{ f } = \frac{ 3.0 \times 10^8 ms^{-1} }{ 6.00 \times 10^{18} s^{-1} } \times \frac{1.0 A}{10^{-10}m}$$ see how the units can be beautifully canceled out whole numbers simplified

17. anonymous

that formula should be provided right? ok i get it now thank you!

18. Astrophysics

An easy way to think of this formula is, think about the units, notice how velocity is m/s, wavelength is m, and if you get frequency don't worry just think about the units and get 1/s. Another way notice how this formula IS exactly like $v = \frac{ d }{ t }$ so that should give you a clue on what's going on.

19. nincompoop

OH ahaha wow I effed that one up

20. nincompoop

let me remove it