anonymous
  • anonymous
math
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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oleg3321
  • oleg3321
well isnt it three students just go into each of the three groups so then all the nine students are split up evenly?
oleg3321
  • oleg3321
did that help?
anonymous
  • anonymous
I do not understand.. Hmm is it 9c3?

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zzr0ck3r
  • zzr0ck3r
9 choose 3
zzr0ck3r
  • zzr0ck3r
\(\frac{9!}{3!(9-3)!}\)
zzr0ck3r
  • zzr0ck3r
\(\dfrac{n!}{k!(n-k)!}\) tells you how many ways you can choose k things from n things.
kropot72
  • kropot72
The number of ways 9 students can be partitioned into three teams containing 3 students each is found as follows: There are 9 choices for the first student of team A, 8 choices for the second student of team A and 7 choices for the third student of team A. The order of the choices does not matter. Therefore the number of ways of choosing team A is given by \[\large \frac{9\times8\times7}{3!}\] Having chosen team A, the number of ways of choosing team B is given by \[\large \frac{6\times5\times4}{3!}\] and the number of ways of choosing team C is given by \[\large \frac{3\times2\times1}{3!}\] Finally the total number of ways is given by \[\large \frac{9!}{3!3!3!}\]
anonymous
  • anonymous
Thank you so much guys.. =)
kropot72
  • kropot72
You're welcome :)

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