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anonymous
 one year ago
I keep getting this wrong, can I please get some help xD
Trying to estimate the area under the graph f(x) = 7 + x^2 using six approximating rectangles and left endpoints (L6).
anonymous
 one year ago
I keep getting this wrong, can I please get some help xD Trying to estimate the area under the graph f(x) = 7 + x^2 using six approximating rectangles and left endpoints (L6).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've already calculated R3, R6, L3, M3, & M6 but I keep getting L6 wrong.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1whats the interval ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Should be 0.5 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Cause it says to use 6 rectangles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh I didn't give you the whole question! Forgive me haha! Here it is... Estimate the area under the graph of f(x)=7+x2 from x=−1 to x=2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get this... \[L _{6}= (7/2)+(7.25/2)+(7/2) +(7.25/2)+(7/2)+(1/2)(7+1.5^2)\] But apparently I'm doing something wrong :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0O.o haha i don't get it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1width of each interval = (21)/6 = 3/6 = 1/2 this is correct in your work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok :) next? What part of my calculations is wrong?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1next, you're splitting the given interval (1, 2) into 6 subinterval sand evaluating the f(x) at the left end point in each subinterval

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1f(x) = 7 + x^2 the first subinterval starts at 1, so the height of first rectangle is 7 + (1)^2 = 7+1 = 8 yes ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I said 7, didn't I? .

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1the second subinterval starts at x = 1 + 1/2 = 1/2 so you need to evaluate f(1/2) for the height of second subinterval

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so area = 1/2*[f(1) + f(1/2) + f(0) + f(1/2) + f(1) + f(3/2)]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Exactly! Thats true! Such a silly mistake :D lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I'm still getting it wrong :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much!!! <3
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