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anonymous

  • one year ago

I keep getting this wrong, can I please get some help xD Trying to estimate the area under the graph f(x) = 7 + x^2 using six approximating rectangles and left endpoints (L6).

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  1. anonymous
    • one year ago
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    I've already calculated R3, R6, L3, M3, & M6 but I keep getting L6 wrong.

  2. ganeshie8
    • one year ago
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    whats the interval ?

  3. anonymous
    • one year ago
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    Should be 0.5 right?

  4. anonymous
    • one year ago
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    Cause it says to use 6 rectangles

  5. anonymous
    • one year ago
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    Ohhh I didn't give you the whole question! Forgive me haha! Here it is... Estimate the area under the graph of f(x)=7+x2 from x=−1 to x=2

  6. anonymous
    • one year ago
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    I get this... \[L _{6}= (7/2)+(7.25/2)+(7/2) +(7.25/2)+(7/2)+(1/2)(7+1.5^2)\] But apparently I'm doing something wrong :/

  7. anonymous
    • one year ago
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    O.o haha i don't get it

  8. ganeshie8
    • one year ago
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    width of each interval = (2--1)/6 = 3/6 = 1/2 this is correct in your work

  9. anonymous
    • one year ago
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    Ok :) next? What part of my calculations is wrong?

  10. ganeshie8
    • one year ago
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    next, you're splitting the given interval (-1, 2) into 6 subinterval sand evaluating the f(x) at the left end point in each subinterval

  11. anonymous
    • one year ago
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    Right

  12. ganeshie8
    • one year ago
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    f(x) = 7 + x^2 the first subinterval starts at -1, so the height of first rectangle is 7 + (-1)^2 = 7+1 = 8 yes ?

  13. anonymous
    • one year ago
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    Yep thats right!

  14. anonymous
    • one year ago
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    Ohhhh >.<

  15. anonymous
    • one year ago
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    I said 7, didn't I? -.-

  16. ganeshie8
    • one year ago
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    the second subinterval starts at x = -1 + 1/2 = -1/2 so you need to evaluate f(-1/2) for the height of second subinterval

  17. anonymous
    • one year ago
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    Right!!

  18. ganeshie8
    • one year ago
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    so area = 1/2*[f(-1) + f(-1/2) + f(0) + f(1/2) + f(1) + f(3/2)]

  19. anonymous
    • one year ago
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    Exactly! Thats true! Such a silly mistake :D lol

  20. anonymous
    • one year ago
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    But I'm still getting it wrong :/

  21. anonymous
    • one year ago
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  22. ganeshie8
    • one year ago
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    try entering 23.375

  23. ganeshie8
    • one year ago
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    or 187/8

  24. anonymous
    • one year ago
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    Thats right! :D

  25. anonymous
    • one year ago
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    Thanks so much!!! <3

  26. ganeshie8
    • one year ago
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    yw!

  27. anonymous
    • one year ago
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    :)

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