anonymous
  • anonymous
Given the functions f(n) = 11 and g(n) = -2(n - 1), combine them to create an arithmetic sequence, an, and solve for the 31st term. (2 points)
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
an = 11 - 2(n - 1); a31 = -49 an = 11 - 2(n - 1); a31 = -51 an = 11 + 2(n - 1); a31 = 71 an = 11 + 2(n - 1); a31 = 73
anonymous
  • anonymous
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Haseeb96
  • Haseeb96
what do you think which one is correct ? @xangelaax
anonymous
  • anonymous
1 or 2 but idk how to find it out
Haseeb96
  • Haseeb96
when we combine these functions we get 11 -2(n-1) ..... eq#1 now to find a31 put n=31 into eq#1 11-2(31-1) 11-2(30) 11-60 -49 is correct answer So 1 is correct answer
anonymous
  • anonymous
thanks so much can you please help with 1 more?
Haseeb96
  • Haseeb96
yes but post it in the new question and click on best response if you like my explanation
anonymous
  • anonymous
okay lol
jiteshmeghwal9
  • jiteshmeghwal9
\[a_n=f(n)+g(n)\]\[a_n=11-2(n-1)\]\[a_{31}=11-2(31-1)\]
anonymous
  • anonymous
thanks that makes sense
anonymous
  • anonymous
i didnt mean to resend that ^^

Looking for something else?

Not the answer you are looking for? Search for more explanations.