1. anonymous

$(3+\sqrt{3},6+\sqrt{2}) and (3-\sqrt{3},6-\sqrt{2})$ find the distance between 2 points . ?

2. IrishBoy123

|dw:1436430937398:dw|

3. anonymous

hmm ? then ? the formula ?

4. Astrophysics

Yes, you can use $d = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}$

5. Astrophysics

Where your coordinates are $(x_1, y_1)~~~\text{and}~~~(x_2,y_2)$ respectively

6. anonymous

so the answer is 0 ?

7. Astrophysics

Nope

8. Astrophysics

$d = \sqrt{((3-\sqrt{3})-(3+\sqrt{3}))^2+((6-\sqrt{2})-(6+\sqrt{2}))^2}$ is what you should have right

9. Astrophysics

$d = \sqrt{(3-\sqrt{3}-3-\sqrt{3})^2+(6-\sqrt{2}-6-\sqrt{2})^2}$ can you finish it off

10. Astrophysics

Notice we distributed the minus signs

11. anonymous

aa.. so the answer is $2\sqrt{5}$

12. Astrophysics

Yeah :)