Let's change f(x) to y so the equation is y=5x-2
The inverse is when you switch y and x so that is x=5y-2
Try and solve it should be easier
so would it be f-^1(x)=-2+5x ????
No because when you divide the 5 you divide the whole equation
so it's f^-1=(x-2)/5
SO IS IT f-^1(x)=x+2/5??
ohh srry i did not see u type that
its alright yeah but keep in mind that both x and 2 are being divided by 5