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anonymous

  • one year ago

Given: AB = CE CD = EF Prove: AB = DF Statement: AB = DF Reason: Substitution Property of Equality Statement: DE = DE Reason: Subtraction Property of Equality Statement: CE = DF Reason: Transitive Property of Equality Statement: CD = DE Reason: Substitution Property of Equality Statement: CE = EF Reason: Transitive Property of Equality

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    if anyone helps ill become their fan

  4. Michele_Laino
    • one year ago
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    here is my resoning: \[\Large \begin{gathered} DF = DE + EF = \hfill \\ = DE + CD = \hfill \\ = CE = \hfill \\ = AB \hfill \\ \end{gathered} \]

  5. anonymous
    • one year ago
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    thx :D can you help me some more? how can you give medals just asking..

  6. Michele_Laino
    • one year ago
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    ok!

  7. anonymous
    • one year ago
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    how tho?

  8. Michele_Laino
    • one year ago
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    you have to click on the "Best Response" button

  9. Michele_Laino
    • one year ago
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    thanks! :)

  10. anonymous
    • one year ago
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    anytime :D can you help with a couple more?

  11. Michele_Laino
    • one year ago
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    ok!

  12. anonymous
    • one year ago
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    :D

  13. anonymous
    • one year ago
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    Points A(-2, 4), B(1, 3), C(4, -1) and D form a parallelogram. What are the coordinates of D? (5, 5) (0, 0) (1, -2) (1, 0) (3, 4)

  14. Michele_Laino
    • one year ago
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    hint: we have the subsequent drawing: |dw:1436446847339:dw|

  15. Michele_Laino
    • one year ago
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    what are the coordinates of point D?

  16. anonymous
    • one year ago
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    1,3

  17. Michele_Laino
    • one year ago
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    are you sure? hint: |dw:1436447202452:dw|

  18. anonymous
    • one year ago
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    lol yes its 1,0 xD i looked at b xD \

  19. Michele_Laino
    • one year ago
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    correct!

  20. anonymous
    • one year ago
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    (Does the happy dance)

  21. Michele_Laino
    • one year ago
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    :)

  22. anonymous
    • one year ago
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    can we do another one?

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spraguer (Moderator)
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