anonymous
  • anonymous
Can someone PLEASE help me out with orgo?!
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
@ganeshie8
Astrophysics
  • Astrophysics
@Empty

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anonymous
  • anonymous
also. |dw:1436510848405:dw|
Astrophysics
  • Astrophysics
Alright, well show your attempt
anonymous
  • anonymous
is it anti markonikov or markovnikov?
anonymous
  • anonymous
I believe it is Markovnikov
Astrophysics
  • Astrophysics
I'm not russian
anonymous
  • anonymous
me neither,. but that's the scientist of which created the law of substituents movements
Astrophysics
  • Astrophysics
Ah interesting, well empty is good at chemistry he can help you with this if he chooses to haha.
anonymous
  • anonymous
|dw:1436511004422:dw|
Astrophysics
  • Astrophysics
esp o chem
anonymous
  • anonymous
lol thanks though
Empty
  • Empty
I don't think this is Markovnikov or antiMarkovnikov, that doesn't really apply here because we're replacing the alcohol with this amine group. Markovnikov sorta stuff is more like how things place on a double bond.
anonymous
  • anonymous
true
anonymous
  • anonymous
but I have a lewis acid here, are there any rules I can apply here?
anonymous
  • anonymous
and I would really appreciate if you could help me out with the first question as well
Empty
  • Empty
The second question I can answer really well I'm not too familiar with amine reactions anymore kinda rusty but I can kinda guess what you'll do. Like I can draw arrows for you.
anonymous
  • anonymous
whatever fits you I would really appreciate any kind of help here
anonymous
  • anonymous
if you prefer the second one then great
Empty
  • Empty
So for the first one, we oxidize it into a keytone to get: |dw:1436511257479:dw| That's just sorta me brainstorming on steps, you still have to remove the alcohol group which won't be very easy so I don't know, I need to go review my Ochem. The second one though I'll explain in a sec.
anonymous
  • anonymous
great thank you so much! and you said you're familiar more with the second question, can you help me with that as well? please?
Empty
  • Empty
For the second one, you have toluene, which really just means methylbenzene. As you may recall, carbon is an electron donating group which is why tertiary carbocations are more stable than secondary carbocations. Since carbon doesn't have any free electrons, I can't exactly draw the resonance properly, but I can do it with aniline which is very similar in that it is electron donating but has NH2 instead of CH3. So we can push electrons around like this: |dw:1436511629053:dw| So aniline and toluene both have higher electron densities at these locations which are called "ortho" and "para" which are relative to the group attached, have you heard of these before?
anonymous
  • anonymous
yes of course
Empty
  • Empty
So how in depth would you like me to go, I can draw out the whole reaction step by step or just say that your major product will be 2-bromotoluene because the reaction is much more common there since it's basically a 2/3 ratio of the possible spots you can hit randomly and the methyl group isn't large enough for stearic bulk to really matter here. You will also get the para product as well as a minor product though, so if you want one or the other you'll have to do other steps like add a protecting group. or purify it afterwards.
anonymous
  • anonymous
can you show the major product?
anonymous
  • anonymous
I just need to see it visually so I could understand the reaction better
Empty
  • Empty
Draw what you think it is, I have already named it and explained it, and if you mess up I can help you out.
anonymous
  • anonymous
cool one sec
anonymous
  • anonymous
|dw:1436512240299:dw|
anonymous
  • anonymous
is that correct?
anonymous
  • anonymous
@Empty ?
Empty
  • Empty
Yeah perfect! Also I just realized how to do your first question easily.
anonymous
  • anonymous
you're brilliant! thank you!
Empty
  • Empty
We add thionyl chloride to turn the alcohol into a good leaving group: |dw:1436512375879:dw|
anonymous
  • anonymous
thank you so much!!!!!
anonymous
  • anonymous
wow you really helped me out here. Thank you su much!
Empty
  • Empty
I can write out the first step better: |dw:1436512464217:dw| Well even that is sorta questionable, the problem is there's such a wide range of people's knowledge in ochem that it's hard to say if my shorthan dis understood or not, but the best part abot Ochem is being able to figure them out by drawing arrows just like you can solve a math problem with algebra. Glad I could help!
anonymous
  • anonymous
help an awesome day!
anonymous
  • anonymous
have*
Empty
  • Empty
Yeah you too, ochem is pretty awesome haha

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