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alright..

now
pour out 6
that is like "subtracting"
x/3 - 6

what we now have is
it is 1/9 full.
any idea how to write that using x?

=x/9?

if i do x/3-6=x/9 then x would equal 27

the point of doing this is not the answer, it is how you get the answer.

okay so I would multiply each side by 9 and get rid of things then it would be 3 multiplied by 9

like this
\[ 9 \cdot \frac{x}{3} - 9 \cdot 6 = 9 \frac{x}{9} \]

so then because it equals 27 (3 times 9 does) would i subtract 6 and have the answer of 21?

the first term
\[ 9\cdot \frac{x}{3} \]
or
\[ \frac{9 \cdot x}{3} \]
you can divide 3 into 9

or, 9/3 is ?

wouldnt it be 9 times x/3

Is this confusing?
If it is , it is worth figuring it out, because algebra uses this a *lot*

yes im super confused

If you have time, you can learn the idea
You know how to figure out
\[ \frac{4}{2} \]
= 2
right?