anonymous
  • anonymous
What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)? (x − 2)2 + (y + 3)2 = 5 (x + 2)2 + (y − 3)2 = 25 (x − 2)2 + (y + 3)2 = 25 (x − 2)2 − (y + 3)2 = 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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alekos
  • alekos
standard form is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the centre and r is the radius
anonymous
  • anonymous
i dont understand how to do it
anonymous
  • anonymous
Is it the third one?

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alekos
  • alekos
centre is (2,-3) so h=2 and k = -3
anonymous
  • anonymous
So the second one
alekos
  • alekos
if you substitute the h and k values you get (x-2)^2 +(y+3)^2 = r^2 so now you have to work out the radius r
alekos
  • alekos
i'll let you do that
anonymous
  • anonymous
25
anonymous
  • anonymous
So the second one
alekos
  • alekos
the radius is the distance between the two points, which is?

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