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anonymous
 one year ago
WILL FAN & MEDAL
Given: m ∠ EGF= 60° and m∠AGF = 90°; Prove: m ∠ AGB = 30°
anonymous
 one year ago
WILL FAN & MEDAL Given: m ∠ EGF= 60° and m∠AGF = 90°; Prove: m ∠ AGB = 30°

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436454054995:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Start with what's given 1) m<EGF = 60 given 2) m<AGF = 90 given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01) m<EGF = 60 Given 2) m<AGF = 90 Given 3) m<BGC = m<EGF Vertical angles are congruent. 4) m<BGC = 60 By transitive property of equality. 5) m<AGF + m<AGC = 180 Linear pair angles are complementary. 6) 90 + m<AGC = 180 By substitution. 7) m<AGC = 90 By subtraction property of equality. 8) m<AGB + m<BGC = m<AGC By angle addition postulate. 9) m<AGB + 60 = 90 By substitution. 10) m<AGB = 30 By subtraction property of equality.

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i see why it says prove why Agb is 30* because I don't believe its 30*

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0agb and agf is same length. Thus being as it is they should both be a 90 degree angle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah 😁 me too but thanks guys
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