***WILL FAN AND MEDAL*** Find the total area the regular pyramid.

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***WILL FAN AND MEDAL*** Find the total area the regular pyramid.

Geometry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is that a regular square pyramid seen from above?

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yes
do they mean surface area?
yes
ok :) let's first find the area of the base that would be a square with a side length of 4
Area of a Square = (side)*(side) = 4 * 4 = ?
16
good :) then let's find the Area of one of the Triangles :3 We need the height of it we are given that the hypotenuse is 4 and half the base (to make a right triangle) is 2 so square root of (4^2 - 2^2) = ?
12
square root of 12 that's right ^_^ it can be simplified to 2 squareroot of 3 then there are 4 triangles so times 4 gives us\[\large 8\sqrt{3}\]
are your options in decimals? :)
we will have to add that 8 root(3) + 16

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