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Falling_In_Katt

  • one year ago

***WILL FAN AND MEDAL*** Find the total area the regular pyramid.

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  1. Falling_In_Katt
    • one year ago
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  2. Falling_In_Katt
    • one year ago
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    @sleepyhead314 @Abhisar @GenTorr

  3. sleepyhead314
    • one year ago
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    is that a regular square pyramid seen from above?

  4. Falling_In_Katt
    • one year ago
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    yes

  5. sleepyhead314
    • one year ago
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    do they mean surface area?

  6. Falling_In_Katt
    • one year ago
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    yes

  7. sleepyhead314
    • one year ago
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    ok :) let's first find the area of the base that would be a square with a side length of 4

  8. sleepyhead314
    • one year ago
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    Area of a Square = (side)*(side) = 4 * 4 = ?

  9. Falling_In_Katt
    • one year ago
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    16

  10. sleepyhead314
    • one year ago
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    good :) then let's find the Area of one of the Triangles :3 We need the height of it we are given that the hypotenuse is 4 and half the base (to make a right triangle) is 2 so square root of (4^2 - 2^2) = ?

  11. Falling_In_Katt
    • one year ago
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    12

  12. sleepyhead314
    • one year ago
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    square root of 12 that's right ^_^ it can be simplified to 2 squareroot of 3 then there are 4 triangles so times 4 gives us\[\large 8\sqrt{3}\]

  13. sleepyhead314
    • one year ago
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    are your options in decimals? :)

  14. sleepyhead314
    • one year ago
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    we will have to add that 8 root(3) + 16

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