anonymous
  • anonymous
the area of a rectangle is 9x^2-9x-4 cm^2. find its length and width then solve the perimeter Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width PLEASE HELP
Mathematics
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schrodinger
  • schrodinger
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alekos
  • alekos
from your roots that would factor out to (3x+1)(3x-4) so what do you think the length and width would be
anonymous
  • anonymous
-1/3 & 4/3? But one of them is negative? :(
anonymous
  • anonymous
uhm ok so the length should be (3x+1) width is (3x-1)? so i'll just substitute the 4/3 here?

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anonymous
  • anonymous
@alekos :) thanks!
alekos
  • alekos
no width is 3x-4
alekos
  • alekos
for perimeter just add l + w
anonymous
  • anonymous
but if x = -1/3 and 4/3 3(4/3) + 1 = 5 3(4/3) - 4 = 0 ???

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