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anonymous
 one year ago
Part 1: Using complete sentences, compare the key features and graphs of sine and cosine. What are their similarities and differences?
Part 2: Using these similarities and differences, how would you transform f(x) = 4 sin(2x  π) + 3 into a cosine function in the form f(x) = a cos(bx  c) + d?
anonymous
 one year ago
Part 1: Using complete sentences, compare the key features and graphs of sine and cosine. What are their similarities and differences? Part 2: Using these similarities and differences, how would you transform f(x) = 4 sin(2x  π) + 3 into a cosine function in the form f(x) = a cos(bx  c) + d?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you compare the sin(x) with the cos(x)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats what i need help with...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we are using radians to measure the angle. if we draw a circle, and measure the angle from the xaxis dw:1436458116835:dw notice that x value will be the cos(x) and the yvalue the sin(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need explaination @0_0youscareme

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now as you turn counterclockwise, the sin x gets bigger (until we reach pi/2 i.e. 90º i.e. pointing straight up) and cos x gets smaller. if we plot the numbers we get the graph I posted up above. notice that when x reaches 2 pi we went around the circle, and everything repeats...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the *only* difference between sin x and cos x is that sin x is shifted by pi/2 as compared to cos x (or vice versa)

0_0youscareme
 one year ago
Best ResponseYou've already chosen the best response.1http://openstudy.com/study#/updates/546ac70ce4b0db932292973e

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you need further help just message me :)
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