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anonymous
 one year ago
the area of a rectangle is 9x^29x4 cm^2.
find its length and width then solve the perimeter
Am I missing something here? The roots are 1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width
PLEASE HELP
anonymous
 one year ago
the area of a rectangle is 9x^29x4 cm^2. find its length and width then solve the perimeter Am I missing something here? The roots are 1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width PLEASE HELP

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amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[ 9x^29x4=(3x+1)(3x4)\\area=\frac{1}{2} base * height =(3x+1)(3x4)\\\]can you go on ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I'm a bit stuck in this part so the length = (3x+1) width = (3x4) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or should I just leave it that way, like I don't have to find the exact value? :)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1base *height =2 (3x+1)(3x4) =(6x+2)(3x4) or (3x+1) (6x8)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1base =(3x+1) height=6x8 and viceversa base =(6x+2) height=3x4 and viceversa

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but I thought the are of a rectangle is just l x w? :)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1oh ...i am sorry i make it for a triangle but it is easier now let's do it again h*w=(3x+1)(3x4) now we have to find 2(h+w) 2((3x+1)+(3x4))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh, okay. So those are the answers? I'll just leave it with all the x's right? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or is there a way we could find the exact values? :((

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1is there any information more ? if not , your question is complete

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, nothing else. thank you so much! :)
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