anonymous
  • anonymous
the area of a rectangle is 9x^2-9x-4 cm^2. find its length and width then solve the perimeter Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width PLEASE HELP
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amoodarya
  • amoodarya
\[ 9x^2-9x-4=(3x+1)(3x-4)\\area=\frac{1}{2} base * height =(3x+1)(3x-4)\\\]can you go on ?
anonymous
  • anonymous
Yeah, I'm a bit stuck in this part so the length = (3x+1) width = (3x-4) ?
anonymous
  • anonymous
or should I just leave it that way, like I don't have to find the exact value? :)

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amoodarya
  • amoodarya
you missed 1/2
amoodarya
  • amoodarya
base *height =2 (3x+1)(3x-4) =(6x+2)(3x-4) or (3x+1) (6x-8)
amoodarya
  • amoodarya
base =(3x+1) height=6x-8 and viceversa base =(6x+2) height=3x-4 and viceversa
anonymous
  • anonymous
but I thought the are of a rectangle is just l x w? :)
anonymous
  • anonymous
*area
amoodarya
  • amoodarya
oh ...i am sorry i make it for a triangle but it is easier now let's do it again h*w=(3x+1)(3x-4) now we have to find 2(h+w) 2((3x+1)+(3x-4))
anonymous
  • anonymous
Ohh, okay. So those are the answers? I'll just leave it with all the x's right? :)
anonymous
  • anonymous
or is there a way we could find the exact values? :((
amoodarya
  • amoodarya
is there any information more ? if not , your question is complete
anonymous
  • anonymous
no, nothing else. thank you so much! :)

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