the area of a rectangle is 9x^2-9x-4 cm^2.
find its length and width then solve the perimeter
Am I missing something here? The roots are -1/3 and 4/3 but I can't seem to figure out how they would come out as the length & width
PLEASE HELP

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\[ 9x^2-9x-4=(3x+1)(3x-4)\\area=\frac{1}{2} base * height =(3x+1)(3x-4)\\\]can you go on ?

Yeah, I'm a bit stuck in this part
so the length = (3x+1)
width = (3x-4)
?

or should I just leave it that way, like I don't have to find the exact value? :)

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