Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.
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okay so im super bad at math so hopefully this wont be wrong |dw:1436459928067:dw|
at the end its 25
When you take the square root of a number, and raise it to second power you should get the number itself.
Such that ( √D )² = D
I mean normally it is equivalent to |D|, but don't worry about that,
you are just cancelling radicals.
yes, so go ahed and try again please for me.
what do you get after raising both sides to the second power?
you have 25 on the right side, and the left side is correct
because 5²=25, you know that right?
then solve for x....
yes, x=3 is correct!
now, to see if this solution is extraneous (if it doesn't work in original equation) or if it is not extraneous (if it DOES work in original equaion), YOU HAVE TO plug in x=3 into your original equation.