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Falling_In_Katt
 one year ago
Find the lateral area the regular pyramid.
L. A. =
Falling_In_Katt
 one year ago
Find the lateral area the regular pyramid. L. A. =

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misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0This is a very awesome tutorial http://www.virtualnerd.com/tutorials/?id=PreAlg_11_01_0031

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0The lateral area of a regular pyramid is 1/2p*l where p is the perimeter of the base and l is the slant height. The lateral formula for a cone is also 1/2p*l where p is the perimeter (or in this case the circumference) of the base and l is the slant height. It can also be shown as pi*r*l, where r is the radius of the base, or 1/2pi*d*l, where d is the diameter of the radius of the base. However, note that this is only the lateral area formula for a right cone. There can be many formulas for the lateral area of an oblique cone. And what they mean when they say they want the answer in terms of pi is that they do not want you to do any process to it. They want the pi to be in the answer. For example, instead of multiplying 3*pi, the answer would instead be 3pi. Or instead of adding 3 + pi, the answer would actually be 3 + pi.

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.0If you'd like more help; please let me know. Truly feel that tutorial should shine some light

perl
 one year ago
Best ResponseYou've already chosen the best response.2the base of that pyramid is a hexagon, and a hexagon is made up of 6 equilateral triangles

perl
 one year ago
Best ResponseYou've already chosen the best response.2If we use this formula 1/2p*L We know p = 6*6 We have to find the slant height L

Falling_In_Katt
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't the slant height be 8?

perl
 one year ago
Best ResponseYou've already chosen the best response.28 is the altitude or height of the pyramid

Falling_In_Katt
 one year ago
Best ResponseYou've already chosen the best response.0Okay so how do I find the slant height?

perl
 one year ago
Best ResponseYou've already chosen the best response.2First let's identify the slant height L . I drew it in purple http://prntscr.com/7qqtha

perl
 one year ago
Best ResponseYou've already chosen the best response.2to find L we can construct a right triangle

perl
 one year ago
Best ResponseYou've already chosen the best response.2we know the leg 8, that is given. the other leg we don't know

perl
 one year ago
Best ResponseYou've already chosen the best response.2but that leg is the altitude for an equilateral triangle as shown here http://prntscr.com/7qqwob

perl
 one year ago
Best ResponseYou've already chosen the best response.2and what do we know about equilateral triangles

perl
 one year ago
Best ResponseYou've already chosen the best response.2an equilateral triangle can be divided into two triangles of 30 60 90 degrees

perl
 one year ago
Best ResponseYou've already chosen the best response.2the ratio of the sides of a 30 60 90 triangle is \( 1 : \sqrt 3 : 2 \)

perl
 one year ago
Best ResponseYou've already chosen the best response.2the height of this triangle is the leg we need

perl
 one year ago
Best ResponseYou've already chosen the best response.2so we need 3 : h : 6 to have same ratio as 1 : sqrt(3) : 2

perl
 one year ago
Best ResponseYou've already chosen the best response.2if you divide through by 3, you get 1 : √3 : 2

Falling_In_Katt
 one year ago
Best ResponseYou've already chosen the best response.0Is 3 the height?

Falling_In_Katt
 one year ago
Best ResponseYou've already chosen the best response.0So I would do \[\frac{ 1 }{ 2 }(6*6)(3\sqrt{3})\]

perl
 one year ago
Best ResponseYou've already chosen the best response.2We can use pythagorean theorem to find L

perl
 one year ago
Best ResponseYou've already chosen the best response.2correct, that would be L^2 take the square root of that

perl
 one year ago
Best ResponseYou've already chosen the best response.2So the lateral area will be $$\Large \frac{ 1 }{ 2 }(6*6)(\sqrt{91})$$
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