anonymous
  • anonymous
Find the hypotenuse of a right triangle whose legs are sqrt of 10 and sqrt of 15. A. sqrt of 5 B. 5 C. 15
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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welshfella
  • welshfella
hypotenuse^2 = h^2 = (sqrt10)^2 + (sqrt15)^2
welshfella
  • welshfella
what is square root of 10 squared?
welshfella
  • welshfella
if, for instance, i took the square root of 16 then squared the answer what would i get?

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welshfella
  • welshfella
or rhe square root of 4 and did the same thing
welshfella
  • welshfella
what is the square root of 4?
anonymous
  • anonymous
2
welshfella
  • welshfella
right and 2 8 2 = ?
welshfella
  • welshfella
2 * 2
welshfella
  • welshfella
- come back to 4 right?
anonymous
  • anonymous
ya
welshfella
  • welshfella
so in the same way take sqrt 10 then i multiply sqrt10 by sqrt10 i get ?
anonymous
  • anonymous
10 sqrt 10?
welshfella
  • welshfella
sqrt4 * sqrt4 = 4 sqrt10 * sqrt10 = ?
anonymous
  • anonymous
10
welshfella
  • welshfella
yes1 by definition thats true also sqrt15 * sqrt15 = 15
welshfella
  • welshfella
so:- hypotenuse^2 = h^2 = (sqrt10)^2 + (sqrt15)^2 h^2 = 10 + 15 h^2 = 25 so h = sqrt 25
anonymous
  • anonymous
Oh! I got it now!!
welshfella
  • welshfella
(remember (sqrt10)^2 = sqrt10 * sqrt10)
welshfella
  • welshfella
good

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