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anonymous

  • one year ago

Find the hypotenuse of a right triangle whose legs are sqrt of 10 and sqrt of 15. A. sqrt of 5 B. 5 C. 15

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  1. welshfella
    • one year ago
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    hypotenuse^2 = h^2 = (sqrt10)^2 + (sqrt15)^2

  2. welshfella
    • one year ago
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    what is square root of 10 squared?

  3. welshfella
    • one year ago
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    if, for instance, i took the square root of 16 then squared the answer what would i get?

  4. welshfella
    • one year ago
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    or rhe square root of 4 and did the same thing

  5. welshfella
    • one year ago
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    what is the square root of 4?

  6. anonymous
    • one year ago
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    2

  7. welshfella
    • one year ago
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    right and 2 8 2 = ?

  8. welshfella
    • one year ago
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    2 * 2

  9. welshfella
    • one year ago
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    - come back to 4 right?

  10. anonymous
    • one year ago
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    ya

  11. welshfella
    • one year ago
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    so in the same way take sqrt 10 then i multiply sqrt10 by sqrt10 i get ?

  12. anonymous
    • one year ago
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    10 sqrt 10?

  13. welshfella
    • one year ago
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    sqrt4 * sqrt4 = 4 sqrt10 * sqrt10 = ?

  14. anonymous
    • one year ago
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    10

  15. welshfella
    • one year ago
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    yes1 by definition thats true also sqrt15 * sqrt15 = 15

  16. welshfella
    • one year ago
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    so:- hypotenuse^2 = h^2 = (sqrt10)^2 + (sqrt15)^2 h^2 = 10 + 15 h^2 = 25 so h = sqrt 25

  17. anonymous
    • one year ago
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    Oh! I got it now!!

  18. welshfella
    • one year ago
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    (remember (sqrt10)^2 = sqrt10 * sqrt10)

  19. welshfella
    • one year ago
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    good

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