Math help!

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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are you familiar with the topics absolute minima/maxima?
Yes
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Other answers:

What does that mean?
thats the set up find an expression for the area of the rectangle in term of x and y then convert it to one variable so you can find the derivative and equate this to zero.
the curve is that of y = 3 - x^2
So I derive this?
Area of the rectangle A = 2xy and we know that y = 3 - x^2 so plug this expression for y into the expression for the area to get the area in terms of x then find dA/dx and equate to 0 and solve for x to find maxm required
* sorry to interfere but quick ques. why is are 2xy? I thought its only xy? thanks!
a=6x-2x^3?
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yes thats correct for the area
a*x*y is only half the area of the whole thing?
|dw:1436464614470:dw|
xy is the area of half the box
agreed?
- though i got the x and y wrong way round
|dw:1436464860013:dw|
A = 6x - 2x^3 dA/dx = 6 - 6x^2 = 0 x^2 = 1 x = 1
oh - talking to myself again!!
Sorry I lost internet connection yesterday but thank you so much! @welshfella

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