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A. Yes because for every input, you have an output (?)

Because each input is related to exactly one output.

This is what i got for Part B: f(11)=5(11)-21 @ienarancillo

Ohh, I had a different way of understanding it :((

honestly i have no idea im so confused.. @ienarancillo

just find x in 5x-21 :)

so its 34? because i plugged in the 11 for x

yeah, meaning that the function in part b has a greater value

as for C, plug in 99 for x

uhm wait a sec,
\[f(x)=y=5x-21\]

\[y=\frac{ 5x }{ 5 }=\frac{ 21 }{ 5 }\]
\[y=f(x)=\frac{ 21 }{ 5 } \approx 4.2\]

but looking at the table,
when x = 11 , y = 8

so comparing
y = 4.2
y = 8
I think you know it form here :)

but please correct me if I'm wrong bc this is how I understood the problem

im still confused :(

let's start from the top

oso we're given f(x)=5x-21 right?

^ from that given equation, do you know how to find x?

* guys please correct me if I'm wrong! :)

yeah i plugged in the 11 for x

Noo, if you plug in x, you'll get y. just dont mind the x=11 first, that's a different function

like y = 5(11)-21
You get y here! Not x! :)

do you get it?

yeaah

sooo transposing ..
we get \[5x = 21\]

and then, we want to find x so divide both sides by 5 \[\frac{ 5x }{ 5 } = \frac{ 21 }{ 5 }\]

so far so good?