can someone help pls. The table shows the outputs y for different inputs x: Input (x) 3 7 11 15 Output (y) 4 6 8 10 Part A: Do the data in this table represent a function? Justify your answer. (3 points) Part B: Compare the data in the table with the relation f(x) = 5x – 21. Which relation has a greater value when x = 11? (2 points) Part C: Using the relation in Part B, what is the value of x if f(x) = 99? (5 points)

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can someone help pls. The table shows the outputs y for different inputs x: Input (x) 3 7 11 15 Output (y) 4 6 8 10 Part A: Do the data in this table represent a function? Justify your answer. (3 points) Part B: Compare the data in the table with the relation f(x) = 5x – 21. Which relation has a greater value when x = 11? (2 points) Part C: Using the relation in Part B, what is the value of x if f(x) = 99? (5 points)

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A. Yes because for every input, you have an output (?)
Because each input is related to exactly one output.
In Part B, you need to find the value of x first in 5x-21, do you know how to do that? If you do, you'll just compare it and conclude your answer!

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This is what i got for Part B: f(11)=5(11)-21 @ienarancillo
Ohh, I had a different way of understanding it :((
from what I understand, there's this f(x) = 5x - 21 right? So, I guess you need to find x first And that is ..?
honestly i have no idea im so confused.. @ienarancillo
just find x in 5x-21 :)
so its 34? because i plugged in the 11 for x
yeah, meaning that the function in part b has a greater value
as for C, plug in 99 for x
uhm wait a sec, \[f(x)=y=5x-21\]
\[y=\frac{ 5x }{ 5 }=\frac{ 21 }{ 5 }\] \[y=f(x)=\frac{ 21 }{ 5 } \approx 4.2\]
but looking at the table, when x = 11 , y = 8
so comparing y = 4.2 y = 8 I think you know it form here :)
but please correct me if I'm wrong bc this is how I understood the problem
im still confused :(
let's start from the top
oso we're given f(x)=5x-21 right?
^ from that given equation, do you know how to find x?
* guys please correct me if I'm wrong! :)
yeah i plugged in the 11 for x
Noo, if you plug in x, you'll get y. just dont mind the x=11 first, that's a different function
like y = 5(11)-21 You get y here! Not x! :)
do you get it?
yeaah
sooo transposing .. we get \[5x = 21\]
and then, we want to find x so divide both sides by 5 \[\frac{ 5x }{ 5 } = \frac{ 21 }{ 5 }\]
so far so good?

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