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anonymous

  • one year ago

Which of the following sets could be the sides of a right triangle? A. {2,3, sqrt of 13} B. {2,2,4} C. (1,2, sqrt of 3 wouldn't it be B because it has all even numbers?

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  1. chrisdbest
    • one year ago
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    No, C

  2. mathstudent55
    • one year ago
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    If a triangle is a right triangle, and the lengths of its sides are a, b, and c, as shown in the figure below, then this equation is true: \(a^2 + b^2 = c^2\) |dw:1436464135669:dw|

  3. chrisdbest
    • one year ago
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    When You do B: 2^2 + 2^2 = 8, and sqrt of 8 is not 4

  4. anonymous
    • one year ago
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    -sighs- im dumb...

  5. SolomonZelman
    • one year ago
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    B is not a triangle, because 2+2\(\bcancel{\Large ~<~}4\)

  6. SolomonZelman
    • one year ago
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    I meant the other way

  7. SolomonZelman
    • one year ago
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    2+2 is not greater than 4

  8. mathstudent55
    • one year ago
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    In a right triangle, the sides labeled a and b are always the sides that form the right angle. They are called legs. The side labeled c is the hypotenuse. It is opposite the right angle, and it is always the longest side in a right triangle.

  9. mathstudent55
    • one year ago
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    For each choice do this: 1. Square each of the shorter sides and add the squares. 2. Then square the longest side. 3. If the sum in step 1. does not equal the number in step 2., then the triangle is not a right triangle.

  10. mathstudent55
    • one year ago
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    Here is choice B.: 1. \(2^2 + 2^2 = 4 + 4 = 8\) 2. \(4^2 = 16\) 3. Since 8 is not equal to 16, choice B is not a right triangle.

  11. mathstudent55
    • one year ago
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    Now do the same to choices A. and B. and see if they are right triangles.

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