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anonymous
 one year ago
The distance (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by equations below:
CAR A: y = 60x + 10
CAR B: y = 40x + 70
After how many hours will the two cars be at the same distance from their starting point and what will that distance be?
A. 2 hours, 150 miles
B. 2 hours, 190 miles
C. 3 hours, 150 miles
D. 3 hours, 190 miles
anonymous
 one year ago
The distance (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by equations below: CAR A: y = 60x + 10 CAR B: y = 40x + 70 After how many hours will the two cars be at the same distance from their starting point and what will that distance be? A. 2 hours, 150 miles B. 2 hours, 190 miles C. 3 hours, 150 miles D. 3 hours, 190 miles

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Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0let's first solve for x \(60x+10=40x+70\) subtract 10 \(60x=40x+60\) subtract 40x \(20x=60\) divide by 20 \(x=3\) so option A and B are out

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0now we solve for y by putting 3 for x in the equation

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.0\(y=60*3+10\\ 60*3=180\\ 180+10=190\\ y=190\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okaay thanksss sooo muchh
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